Given options : Two intersecting circles are drawn with a radius in each marked. the image will be linked.
Given options : An equilateral triangle inscribed in a circle
A square inscribed in a circle
A regular pentagon inscribed in a circle
A regular hexagon inscribed in a circle.
<u>Note. When we join an intersection point of two circles and centers of the circles it would form an equilateral triangle that would be inscribe inside a common portion of both circles..</u>
Therefore, an equilateral triangle inscribed in a circle would be correct option.
She is completing an equilateral triangle inscribed in a circle.
Answer:
I kinda did a lil of this in my head so i might not be 100% correct, but i would say the bigger group is 20 and the smaller group is 10
Answer:
y = 1/3x - 19/3
Step-by-step explanation:
3y = x -3
y = 1/3x -3
Slope = 1/3
Point= (1,-6)
y-intercept = -6 - (1/3)(1) = -6 - 1/3 = -19/3
Taking the derivative of 7 times secant of x^3:
We take out 7 as a constant focus on secant (x^3)
To take the derivative, we use the chain rule, taking the derivative of the inside, bringing it out, and then the derivative of the original function. For example:
The derivative of x^3 is 3x^2, and the derivative of secant is tan(x) and sec(x).
Knowing this: secant (x^3) becomes tan(x^3) * sec(x^3) * 3x^2. We transform tan(x^3) into sin(x^3)/cos(x^3) since tan(x) = sin(x)/cos(x). Then secant(x^3) becomes 1/cos(x^3) since the secant is the reciprocal of the cosine.
We then multiply everything together to simplify:
sin(x^3) * 3x^2/ cos(x^3) * cos(x^3) becomes
3x^2 * sin(x^3)/(cos(x^3))^2
and multiplying the constant 7 from the beginning:
7 * 3x^2 = 21x^2, so...
our derivative is 21x^2 * sin(x^3)/(cos(x^3))^2
Answer:
No
Step-by-step explanation:
