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Lyrx [107]
3 years ago
5

Use the equation 1/2 (x - 4) = 1/3x + 2

Mathematics
2 answers:
Margarita [4]3 years ago
8 0

Answer:

Step-by-step explanation:

Multiply the whole equation by 6  (LCM  of 2 and 3)

1/2 (x - 4) = 1/3x + 2

6* 1/2 (x - 4) = 6* (1/3x + 2)

3 (x - 4) = 6* 1/3x + 6*2

3x - 12 = 2x + 12

3x -2x = 12 + 12

x = 24

Anon25 [30]3 years ago
5 0

Answer:

1/2(x-4)= 1/3x+2

6x1/2(x-4)=6x1/3x+2x6

3(x-4)=2x+12

3x-12=2x+12

3x-2x=12+12

x=24

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If £25 = 800 rubles, how many £ are in 992 rubles?​
katen-ka-za [31]

Answer:

£31

Step-by-step explanation:

25 = 800

x = 992

x = 992 x 25 / 800 = 31

3 0
2 years ago
In the month of June, the temperature in Johannesburg, South Africa, varies over the day in a periodic way that can be modeled a
Art [367]

Answer:

The answer is "\bold{T = - 7.5 \cos \frac{\pi}{12}( t - 4 )+ 10.5}"

Step-by-step explanation:

Given value:

Temp-maximum=18^{\circ}  

Temp. minimum = 3^{\circ}

It is halfway between 10 am and 10 pm to 4 am.  

The sinus and cosine roles could be used throughout the year to predict fluctuations in climate models. Its type of formula that can be used to model such information is:  

T = A \cos B(t-C) + D, where parameters are A, B , C, D, T is the ° C temperature and t is the time (1-24)

A = amplitude = \frac{(T_{max} - T_{min})}{2}\\\\

                       = \frac{(3 - 18)}{2}\\\\= - \frac{15}{2}\\\\ = -7.5

B = \frac{2 \pi}{24}\\\\

   = \frac{\pi}{12}

C = \text{ units translated to the right}= 4

D = y_{min} + amplitude = units \ translated \ up\\\\

D = 7.5 + 3 = 10.5

Its trigonometric function equation that model temperature T hours after midnight in Johannesburg t.

T = - 7.5 \cos \frac{\pi}{12}( t - 4 )+ 10.5

6 0
3 years ago
How do you solve the equation F = 9/5(K - 273.15) + 32 when you're solving for K?
Mumz [18]

\displaystyle\\Answer:\ K=\frac{5}{9}(F-32^0)+273.15^0

Step-by-step explanation:

\displaystyle\\F=\frac{9}{5} (K-273.15)+32\\F-32=\frac{9}{5} (K-273.15)+32-32\\F-32=\frac{9}{5} (k-273.15)\\Multiply\  both\  parts\  of\  the\  equation\  by\ \frac{5}{9} \\(\frac{5}{9})(F-32)=\frac{9}{5}  (K-273.15)(\frac{5}{9} )\\\\\frac{5}{9} (F-32)=K-273.15\\\\\frac{5}{9} (F-32)+273.15=K-273.15+273.15\\\\\frac{5}{9} (F-32)+273.15=K

7 0
1 year ago
Look at the graph. which equation represents the graph?
Svetllana [295]
The correct answer is A
4 0
2 years ago
What is the solution for: 10n^2+n^2+16
ivanzaharov [21]

The solution is n= <u>+</u> 4i/√11

Step-by-step explanation:

step 1: 10n^2+n^2+16=0

step 2: 11n^2+16=0

step 3: 11n^2= -16

step 4: n^2= -16/11

step 5: taking square root on both sides,

            n= √(-16)/√11 (square root of a negative number is a <u>complex term</u> 'i')

            n= <u>+</u> 4i/√11

3 0
3 years ago
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