A car travels 100 meter in 5 seconds . What is the speed of the car

Select the correct answer from the drop-down menu.

ELEN [110]

Missing term = –2xy

Solution:

Let us first find the quotient of $-8x^2y^3 \div xy$ .

$-8x^2y^3 \div xy=\frac{-8x^2y^3 }{xy}$

$=\frac{-8\times x\times x\times y\times y\times y}{xy}$

Taking common term xy outside in the numerator.

$=\frac{xy(-8\times x\times y\times y)}{xy}$

Both xy in the numerator and denominator are cancelled.

$=-8xy^2$

Thus, the quotient of $-8x^2y^3 \div xy$ is $-8xy^2$ .

Given the quotient of $-8x^2y^3 \div xy$ is same as the product of 4xy and ____.

$-8xy^2=4xy$ × missing term

Divide both sides by 4xy, we get

⇒ missing term = $\frac{-8xy^2}{4xy}$

Cancel the common terms in both numerator and denominator.

⇒ missing term = –2xy

Hence the missing term of the product is –2xy.

4 0

3 years ago

rename 1/2 and 2/3 as fractions with denominators of 6.then add the renamed fractions. write the sum as a mixed number.

monitta

Answer:

1 and 1/6

Step-by-step explanation:

To rename a fraction you multiply both numbers by however many times the original denominator goes into the new one.

2 goes into 6 three times.

1 times 3 is 3

and 2 times 3 is 6

so 1/2=3/6

3 goes into 6 twice

2 times 2 is 4

and 2 times 3 is 6

so 2/3=4/6

to add fractions you add the numerators while keeping the denominators the same.

3+4=7 so:

3/6+4/6=7/6

6/6=1

so 7/6 contains 1 whole

once you take that out you have 1/6 left over

4 0

2 years ago

Two teams A and B play a series of games until one team wins three games. We assume that the games are played independently and

Olenka [21]

Answer:

The probability that the series lasts exactly four games is $3p(1-p)(p^{2} + (1 - p)^{2})$

Step-by-step explanation:

For each game, there are only two possible outcomes. Either team A wins, or team A loses. Games are played independently. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

We also need to know a small concept of independent events.

Independent events:

If two events, A and B, are independent, we have that:

$P(A \cap B) = P(A)*P(B)$

What is the probability that the series lasts exactly four games?

This happens if A wins in 4 games of B wins in 4 games.

Probability of A winning in exactly four games:

In the first two games, A must win 2 of them. Also, A must win the fourth game. So, two independent events:

Event A: A wins two of the first three games.

Event B: A wins the fourth game.

P(A):

A wins any game with probability p. 3 games, so n = 3. We have to find P(A) = P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(A) = P(X = 2) = C_{3,2}.p^{2}.(1-p)^{1} = 3p^{2}(1-p)$

P(B):

The probability that A wins any game is p, so P(B) = p.

Probability that A wins in 4:

A and B are independent, so:

$P(A4) = P(A)*P(B) = 3p^{2}(1-p)*p = 3p^{3}(1-p)$

Probability of B winning in exactly four games:

In the first three games, A must win one and B must win 2. The fourth game must be won by 2. So

Event A: A wins one of the first three.

Event B: B wins the fourth game.

P(A)

P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(A) = P(X = 1) = C_{3,1}.p^{1}.(1-p)^{2} = 3p(1-p)^{2}$

P(B)

B wins each game with probability 1 - p, do P(B) = 1 - p.

Probability that B wins in 4:

A and B are independent, so:

$P(B4) = P(A)*P(B) = 3p(1-p)^{2}*(1-p) = 3p(1-p)^{3}$

Probability that the series lasts exactly four games:

$p = P(A4) + P(B4) = 3p^{3}(1-p) + 3p(1-p)^{3} = 3p(1-p)(p^{2} + (1 - p)^{2})$

The probability that the series lasts exactly four games is $3p(1-p)(p^{2} + (1 - p)^{2})$

8 0

3 years ago

1<br> Which graph represents the linear function below?

Mamont248 [21]

The graph that represents the given linear function is attached below.

We are given a function. A function connects an input with an output. It is analogous to a machine with an input and an output. And the outcome is somehow connected to the input. The equation is linear in nature. It represents a straight line. The equation is given below.

(y - 4) = (4/3)(x - 2)

A line's general equation in slope-intercept form is y = mx + c. We will convert the given equation into this form.

y - 4 = (4/3)x - 8/3

y = (4/3)x - 8/3 + 4

y = (4/3)x + 4/3

The slope of the given equation is 4/3. The y-intercept for the given equation is 4/3.

To learn more about functions, visit :

brainly.com/question/5975436

#SPJ1

3 0

8 months ago

There are 7 brothers and 6 sisters. If all siblings sat in a row and the girls requested to be seated next to one another, how m

SashulF [63]

<h3>Answer: 29,030,400</h3>

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Explanation:

Let's say the mother will temporarily take the place of all the sisters. Wherever the mother sits will represent the block of girls.

Taking out the 6 sisters and replacing them with the mother leads to 7+1 = 8 people in a line.

There are 8! = 8*7*6*5*4*3*2*1 = 40,320 different ways to arrange 8 people.

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Again, the mother's position is where the sisters block will go. So let's say the mother was in seat #2. This would mean one brother would take seat #1, and all of the sisters would take the next six seats, until we reach seat #7 is when another brother would take the next seat.

Within any given permutation (the 40320 mentioned), there are 6! = 6*5*4*3*2*1 = 720 different ways to arrange just the girls in that girls block/group.

All together, there are 40320*720 = 29,030,400 different ways to arrange the 13 siblings where all the girls are seated together.

7 0

3 years ago