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irga5000 [103]
3 years ago
6

If rs =3x + 1, st = 2x- 2 ,and rt = 64,find the value of x

Mathematics
1 answer:
stealth61 [152]3 years ago
3 0
             rs + st = rt     Plug in the values
3x + 1 + 2x - 2 = 64   Combine like terms (1 and -2)
       3x -1 + 2x = 64   Combine like terms (3x and 2x)
            -1 + 5x = 64   Add 1 to both sides
                  5x = 65   Divide both sides by 5
                    x = 13
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Answer:

You would pay $2.75

Step-by-step explanation:

a dozen = 12

6.60 / 12 = $0.55

0.55 x 5 = 2.75

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Find the solution set for this equation:<br> -a2+4a=0<br> (Separate the two values with a comma)
Rashid [163]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: \{ 0,4 \}

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \: -  {a}^{2}  + 4a = 0

\qquad \tt \rightarrow \: - ( {a}^{2}  - 4a) = 0

\qquad \tt \rightarrow \: {a}^{2}  - 4a = 0

\qquad \tt \rightarrow \:a(a - 4) = 0

The two cases are :

  • a = 0

or

  • a -4 = 0, that leads to a = 4

We can conclude :

\qquad \tt \rightarrow \:solution \: (a)  = \{ 0,4\}

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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Find the area of the circle whose equation is x2+y2=6x-8y​
Semenov [28]

Answer:

Given that the equation of a circle is :

\green{ \boxed{\boxed{\begin{array}{cc}  {x}^{2}  +  {y}^{2}  = 6x - 8y \\  =  >  {x}^{2}  +  {y}^{2}   - 6x + 8y = 0 \\  =  >  {x}^{2}  +  {y}^{2}  + 2 \times ( - 3) \times x + 2 \times 4 \times y = 0 \\  \\  \sf \: standard \: equation \: o f \: circle \: is :  \\   {x}^{2}  +  {x}^{2}  + 2gx + 2fy + c = 0 \\  \\  \sf \: by \: comparing \\  \\ g =  - 3 \\ f = 4 \\ c = 0 \\  \\  \sf \: radius \:  \: r =  \sqrt{ {g}^{2}  +  {f}^{2} - c }  \\  =  \sqrt{ {( - 3)}^{2} +  {4}^{2} - 0  }  \\  =  \sqrt{9 + 16}  \\   = \sqrt{25}  \\  = 5 \: unit \\  \\  \bf \: area \:  = \pi {r}^{2}  \\  = \pi \times  {5}^{2}  \\  =\pink{ 25\pi \:  { unit }^{2} }\end{array}}}}

6 0
3 years ago
Punctele O, A, B, C sunt coliniare în această ordine, iar segmentele OA, AB și BC au lungimile exprimate în cm, prin numere natu
julia-pushkina [17]

Răspuns:

a) OC = 18cm

b) MN = 6cm

Explicație pas cu pas:

Găsiți diagrama la întrebarea atașată.

a) Din diagramă se poate observa că OC = OA + AB + AC

OC = 2n + 2n + 2 + 2n + 4

OC = 6n + 6

Următorul este să obțineți valoarea lui n:

OM = OA + AM

Să obținem segmentul AM;

Deoarece M este segmentul mijlociu al AC, atunci;

AM = AC / 2

AM = AB + BC / 2

AM = 2n + 2 + 2n + 4/2

AM = 4n + 6/2

AM = 2n + 3

Din moment ce OM = OA + AM

OM = 2n + 2n + 3

OM = 4n + 3

Dat fiind OM = 11

11 = 4n + 3

4n = 11-3

4n = 8

n = 2

Următorul pas este să calculați OC;

OC = 6n + 6

OC = 6 (2) + 6

OC = 18

Prin urmare, lungimea segmentului OC este de 18 cm

b) Această întrebare ne cere să găsim segmentul de linie MN.

Din diagramă, MN = AM - AN

Deoarece AM = 2n + 3 din întrebarea 1;

AM = 2 (2) +3

AM = 4 + 3

AM = 7

Acum, să obținem AN:

Din diagramă, AN = ON-OA și ON = OB / 2

AN = OB / 2 - OA

AN = (2n + 2n + 2) / 2 - 2n

AN = 4n + 2/2 - 2n

AN = 2n + 1 - 2n

AN = 2n-2n + 1

AN = 1

De la MN = AM - AN

MN = 7 - 1

MN = 6cm

Prin urmare, distanța dintre N, mijlocul segmentului OB și punctul M este de 6cm

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kaheart [24]

Answer:

The given expression is a cubic polynomial with degree 3.

Step-by-step explanation:

We are given the following in the question:

3x^3-x^2

Polynomial:

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  • The variables and coefficients involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables.

Since, the given expression satisfies all the properties, it is a polynomial.

Degree of polynomial:

  • It is the maximum degree of the polynomial.

The degree of given polynomial is 3.

Nature of polynomial:

It is a cubic polynomial.

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3 years ago
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