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irga5000 [103]
3 years ago
6

If rs =3x + 1, st = 2x- 2 ,and rt = 64,find the value of x

Mathematics
1 answer:
stealth61 [152]3 years ago
3 0
             rs + st = rt     Plug in the values
3x + 1 + 2x - 2 = 64   Combine like terms (1 and -2)
       3x -1 + 2x = 64   Combine like terms (3x and 2x)
            -1 + 5x = 64   Add 1 to both sides
                  5x = 65   Divide both sides by 5
                    x = 13
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Answer:

(x+6)(x-1)

Step-by-step explanation:

x^2+6x-x-6

x(x+6)-(x+6)

(x+6)(x-1)

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Jasmine purchased a laptop worth $1,500 in 2007. It loses its value by %32 each year. What is the value of the laptop in 2010? R
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Step-by-step explanation:

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P_t=P_o(1-d)^t

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P_o is the initial value

d is the rate of depreciation

t is the time

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8 0
3 years ago
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Read 2 more answers
The function f(x)= -6x+11 has a range given by {-37,-25,-13,-1}.Select the domain values of the function from the list 1,2,3,4,5
andreev551 [17]
The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this
function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.

So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11)
one by one.

f(1)=-6(1)+11=5
f(2)=-6(2)+11= -1
f(3)=-6(3)+11= -7
f(4)=-6(4)+11= -13
f(5)=-6(5)+11= -19
f(6)=-6(6)+11= -25
f(7)=-6(7)+11= -31
f(8)=-6(8)+11= -37
As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.
4 0
3 years ago
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