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3 years ago

I will give the BRAINIEST!!! Please help!!

Mathematics

1 answer:

pishuonlain [190]3 years ago

3 0

Answer:

a. y= -5/2x -4

Step-by-step explanation:

An equation that is perpendicular to another equation must have the opposite slope. In other words, the perpendicular equation will be the opposite sign & the reciprocal of the equation it is perpendicular to. In this case, the perpendicular slope is -5/2x. Therefore, the only answer possible is a.

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Which is the equation of a line that has a slope of 1 and passes through point (5, 3)?

Montano1993 [528]

Answer:

Step-by-step explanation:

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2 years ago

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Mr. Smith built a rectangular-shaped sandbox for his children, measuring 4 feet by 4 feet by 6 inches. Sand has a density of app

ehidna [41]

Answer:

To completely fill the sandbox will cost $56

Step-by-step explanation:

First, we calculate volume of the rectangular-shaped sandbox:

$V=long*with*height\\V=4feet*4feet*0.5feet\\V=8cubicfoot$

We know that density of sand is 100 pounds per cubic foot. Then, to fill the sand box that has a volume of 8 cubic foot, we calculate by rule 3:

1cubic foot..............100 pounds

8 cubic foot.............x pounds

$x=\frac{8*100}{1}$

$x=800 pounds$

We will need 800 pounds of sand to fill the sandbox, then we can calculate by rule 3 the number of bags needed and next the total cost of them:

50 pounds.......1bag

800 pounds.....x bags

$x=\frac{800*1}{50} \\x=16$

To calculate the cost:

1 bag ..................$3.50

16 bags.................$x

$x=16*3.50\\x=$56$

To completely fill the sandbox will cost $56

4 0

3 years ago

1 point

ludmilkaskok [199]

18n+4.4m I don’t know if this is right but I don’t understand the information you gave me because the numbers are scrambled

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3 years ago

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Find all the complex roots. Write the answer in exponential form.

dezoksy [38]

We have to calculate the fourth roots of this complex number:

$z=9+9\sqrt[]{3}i$

We start by writing this number in exponential form:

$\begin{gathered} r=\sqrt[]{9^2+(9\sqrt[]{3})^2} \\ r=\sqrt[]{81+81\cdot3} \\ r=\sqrt[]{81+243} \\ r=\sqrt[]{324} \\ r=18 \end{gathered}$ $\theta=\arctan (\frac{9\sqrt[]{3}}{9})=\arctan (\sqrt[]{3})=\frac{\pi}{3}$

Then, the exponential form is:

$z=18e^{\frac{\pi}{3}i}$

The formula for the roots of a complex number can be written (in polar form) as:

$z^{\frac{1}{n}}=r^{\frac{1}{n}}\cdot\lbrack\cos (\frac{\theta+2\pi k}{n})+i\cdot\sin (\frac{\theta+2\pi k}{n})\rbrack\text{ for }k=0,1,\ldots,n-1$

Then, for a fourth root, we will have n = 4 and k = 0, 1, 2 and 3.

To simplify the calculations, we start by calculating the fourth root of r:

$r^{\frac{1}{4}}=18^{\frac{1}{4}}=\sqrt[4]{18}$

<em>NOTE: It can not be simplified anymore, so we will leave it like this.</em>

Then, we calculate the arguments of the trigonometric functions:

$\frac{\theta+2\pi k}{n}=\frac{\frac{\pi}{2}+2\pi k}{4}=\frac{\pi}{8}+\frac{\pi}{2}k=\pi(\frac{1}{8}+\frac{k}{2})$

We can now calculate for each value of k:

$\begin{gathered} k=0\colon \\ z_0=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{0}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{0}{2}))) \\ z_0=\sqrt[4]{18}\cdot(\cos (\frac{\pi}{8})+i\cdot\sin (\frac{\pi}{8}) \\ z_0=\sqrt[4]{18}\cdot e^{i\frac{\pi}{8}} \end{gathered}$ $\begin{gathered} k=1\colon \\ z_1=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{1}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{1}{2}))) \\ z_1=\sqrt[4]{18}\cdot(\cos (\frac{5\pi}{8})+i\cdot\sin (\frac{5\pi}{8})) \\ z_1=\sqrt[4]{18}e^{i\frac{5\pi}{8}} \end{gathered}$ $\begin{gathered} k=2\colon \\ z_2=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{2}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{2}{2}))) \\ z_2=\sqrt[4]{18}\cdot(\cos (\frac{9\pi}{8})+i\cdot\sin (\frac{9\pi}{8})) \\ z_2=\sqrt[4]{18}e^{i\frac{9\pi}{8}} \end{gathered}$ $\begin{gathered} k=3\colon \\ z_3=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{3}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{3}{2}))) \\ z_3=\sqrt[4]{18}\cdot(\cos (\frac{13\pi}{8})+i\cdot\sin (\frac{13\pi}{8})) \\ z_3=\sqrt[4]{18}e^{i\frac{13\pi}{8}} \end{gathered}$

Answer:

The four roots in exponential form are

z0 = 18^(1/4)*e^(i*π/8)

z1 = 18^(1/4)*e^(i*5π/8)

z2 = 18^(1/4)*e^(i*9π/8)

z3 = 18^(1/4)*e^(i*13π/8)

5 0

1 year ago

Find:P(large or blue)

siniylev [52]

Answer:

7/10

Step-by-step explanation:

Total number = 17+3+8+12 = 40

The ones that are large are 17 and 8

The ones that are blue are 17 and 3

Do not count the 17 twice

P(large or blue) = (17+3+8)/40

= 28/40

=7/10

7 0

3 years ago