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horsena [70]
3 years ago
5

When a program has several modules calling other modules, programmers often use a program ____, which operates similarly to an o

rganizational chart, to show the overall picture of how modules are related to one another.
Computers and Technology
1 answer:
maw [93]3 years ago
3 0

Answer:

hierarchy chart

Explanation:

Based on the information provided within the question it can be said that in this scenario programmers usually use a hierarchy chart. This is a chart that shows the relationship that exists between various different modules that are able to call on another. Therefore showing the programmers the organization of the entire overall program.

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In an office there is a unisex bathroom with n toilets. The bathroom is open to both men and women, but it cannot be used by men
Gnesinka [82]

Answer:

Check the explanation

Explanation:

#include <stdio.h>

#include <stdlib.h>

#include <pthread.h>

#include <semaphore.h>

int mcount,wcount;

sem_t x,y,z,wsem,msem,cap;

void delay(void)

{

int i;

int delaytime;

delaytime = random();

for (i = 0; i<delaytime; i++);

}

void *woman(void *param)

{

sem_wait(&z);

sem_wait(&wsem);

sem_wait(&y);

wcount++;

if(wcount==1)

{ sem_wait(&msem); }

sem_post(&y);

sem_post(&wsem);

sem_post(&z);

sem_wait(&cap);

printf("woman in!\n");

delay();

printf("\twoman out!\n");

sem_post(&cap);  

sem_wait(&y);

wcount--;

if(wcount==0)

{ sem_post(&msem); }

sem_post(&y);

}

void *man(void *param)

{  

sem_wait(&z);

sem_wait(&msem);

sem_wait(&x);

mcount++;

if(mcount==1)

{ sem_wait(&wsem); }

sem_post(&x);

sem_post(&msem);

sem_post(&z);

sem_wait(&cap);

printf("\t\tman in!\n");

delay();

printf("\t\t\tman out!\n");

sem_post(&cap);

sem_wait(&x);

mcount--;

if(mcount==0)

{sem_post(&wsem);}

sem_post(&x);

}

int main(void)

{

int i;

srandom(60);

mcount = 0;

wcount = 0;

sem_init(&x,0,1); // for sem_init, initial value is 3rd argument

sem_init(&y,0,1);

sem_init(&z,0,1);

sem_init(&wsem,0,1);

sem_init(&msem,0,1);

sem_init(&cap,0,4); // eg. cap initialized to 4

pthread_t *tid;

tid = malloc(80*sizeof(pthread_t));

// You can use your cobegin statement here, instead of pthread_create()  

// I have forgone the use of pthread barriers although I suppose they would nicely imitate the functionality of cobegin.

// This is merely to retain simplicity.

for(i=0;i<10;i++)

{

pthread_create(&tid[i],NULL,woman,NULL);

}

for(i=10;i<20;i++)

{  

pthread_create(&tid[i],NULL,man,NULL);

}

for(i=0;i<20;i++)

{  

pthread_join(tid[i],NULL);

}

return(0);

}

5 0
3 years ago
Write a Python program which asks a user for a word and performs letters manipulation. If the word is empty, the program should
never [62]

Answer:

The program is as follows:

word = input("Enter a word: ")

if word:

   if len(word) <= 4:

       word = word[::-1]

   else:

       word = word[0]+word[1]+word[-2]+word[-1]

   print(word)

else:

   print('empty!')

Explanation:

This gets input for word from the user

word = input("Enter a word: ")

If input is not empty

if word:

This checks if the length is less than or equal to 4 characters

   if len(word) <= 4:

If yes, this reverses the word

       word = word[::-1]

If otherwise,

   else:

This gets the first, second, second to last two characters

       word = word[0]+word[1]+word[-2]+word[-1]

Print the new string

   print(word)

Print empty, if input is empty

<em>else: </em>

<em>    print('empty!')</em>

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Question 12 (2 points)
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UkoKoshka [18]

Answer:

// Program is written in C++ Programming Language

// Comments are used for explanatory purpose

// Program starts here

#include<iostream>

using namespace std;

int main()

{

// Declare integer variable n which serves as the quotient.

int n;

// Prompt to enter any number

cout<<"Enter any integer number: ";

cin>>n;

// Check for divisors using the iteration below

for(int I = 1; I<= n; I++)

{

// Check if current digit is a valid divisor

if(n%I == 0)

{

// Print all divisors

cout<<I<<" ";

}

}

return 0;

}

7 0
3 years ago
Every page on a website must be updated recently to consider the website updated/maintained
guajiro [1.7K]
Unmaintained. hope that helped
6 0
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