Answer:
See explaination for the code
Explanation:
def wordsOfFrequency(words, freq):
d = {}
res = []
for i in range(len(words)):
if(words[i].lower() in d):
d[words[i].lower()] = d[words[i].lower()] + 1
else:
d[words[i].lower()] = 1
for word in words:
if d[word.lower()]==freq:
res.append(word)
return res
Note:
First a dictionary is created to keep the count of the lowercase form of each word.
Then, using another for loop, each word count is matched with the freq, if it matches, the word is appended to the result list res.
Finally the res list is appended.
A statement best describes the Tell Me feature in PowerPoint 2016 is that: D. it opens a search field that can be used to look up old versions of presentations.
<h3>What is PowerPoint 2016?</h3>
PowerPoint 2016 refers to a software application that was designed and developed by Microsoft Inc., so as to avail its end users the ability to create various slides which can be used during a presentation.
In PowerPoint 2016, the Tell Me feature is a tool which opens a search field that can be used by end users to look up or search old versions of presentations.
Read more on PowerPoint here: brainly.com/question/26404012
#SPJ1
Answer:
Written in C++
void number(int n){
if(n%2 == 0)
cout<<2 * n;
else
cout<<5 * n;
}
Explanation:
The programming language is not stated.
However, I answered using C++
This line defines the function as void
void number(int n){
This line checks if the number is even
if(n%2 == 0)
If yes, it doubles the number and prints the output
cout<<2 * n;
If otherwise,
else
It multiplies the number by 5 and prints the output
cout<<5 * n;
}
To call the function from main, use:
number(n);
Note than n must be declared as integer
See attachment
