Answer:
#program in Python
#read until user Enter an integer
while True:
#try block to check integer
try:
#read input from user
inp = int(input("Enter an integer: "))
#print input
print("The integer is: ",inp)
break
#if input is not integer
except ValueError:
#print message
print("Wrong: try again.")
Explanation:
In try block, read input from user.If the input is not integer the print a message in except block.Read the input until user enter an integer. When user enter an integer then print the integer and break the loop.
Output:
Enter an integer: acs
Wrong: try again.
Enter an integer: 4a
Wrong: try again.
Enter an integer: 2.2
Wrong: try again.
Enter an integer: 12
The integer is: 12
Maybe 7411 or someones birthday in the family
Answer:
t= 8.7*10⁻⁴ sec.
Explanation:
If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.
As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.
Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:
If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:
⇒ t = 8.7*10⁻⁴ sec.
Answer:
d. The trigger is fired more than once.
Explanation:
What would happen in this situation is that the trigger would be fired more than once. This is because the trigger will be fired when the user updates the record. It will also be fired when the process builder is run.
If the trigger fires more than once, this can be problematic for the developer. Therefore, it is better if the trigger fires just once, as this is the time when the present changes can be placed.
They are based on 10 digits.
I’m not sure.
