Answer:
x = 0
Step-by-step explanation:simplified is 8x-5y=0
Answer:
The result is the same.
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
Please have a look at the attached photo.
My answer:
Given the information:
- square 12 inches wide
- 3-inch diameter cookies are cut => its radius is: 1.5 inches
Hence we can find some information:
- The area of the square is:
square inches - The area of a cookies is:
π = 3.14*
= 7.065 square inches - The total number of 3-inch cookies are: 4*4 =16
=> The total area of the cookies is: 16* 7.065 = 113.04 square inches
=> how much cookie dough is "wasted" when 3-inch cookies are cut:
= The area of the square - The total area of the cookies
= 144 - 113.04 = 30.96 square inches
If the diameter is increased to 4 inches => its radius: 2 inches, we have:
- The area of a cookies is:
π =
square inches - The total number of 3-inch cookies are: 3*3 =9
=> The total area of the cookies is: 9* 12.56 = 113.04 square inches
=> how much cookie dough is "wasted" when 4-inch cookies are cut:
= The area of the square - The total area of the cookies
= 144 - 113.04 = 30.96 square inches
The result is the same.
Parenthesis first
11+4=15
division second
15/3=5
what is the square root of 64? 8!
8x5=40
Answer is 40
Answer:
The figure is attached and the total distance is 1031 feet.
Step-by-step explanation:
The graph is indicated in the attached figure.
For calculation of distance consider following
Point Flagpole is (0,0)
Point Clue1 is (0,5)
Point Clue2 is (6,0)
Point Clue3 is (0,-5)
So the distance is calculated as follows
Substituting the values
![d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\](https://tex.z-dn.net/?f=d_%7BT%7D%3D%5B%5Csqrt%7B%280-0%29%5E2%2B%285-0%29%5E2%7D%2B%5Csqrt%7B%286-0%29%5E2%2B%280-5%29%5E2%7D%2B%5Csqrt%7B%280-6%29%5E2%2B%28-5-0%29%5E2%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B%280%29%5E2%2B%285%29%5E2%7D%2B%5Csqrt%7B%286%29%5E2%2B%28-5%29%5E2%7D%2B%5Csqrt%7B%28-6%29%5E2%2B%28-5%29%5E2%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B0%2B25%7D%2B%5Csqrt%7B36%2B25%7D%2B%5Csqrt%7B36%2B25%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B%5Csqrt%7B25%7D%2B%5Csqrt%7B61%7D%2B%5Csqrt%7B61%7D%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B5%2B7.81%2B7.81%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D%5B20.62%5D%2A50%20%5Ctext%7B%20feet%7D%5C%5Cd_%7BT%7D%3D1031%20%5Ctext%7B%20feet%7D%5C%5C)
So the total distance travelled is 1031 feet.