How many ways can a group of three boys and three girls be seated in a row of six seats if boys and girls must alternate in the
1 answer:
Answer:
24
Step-by-step explanation:
there are 6 seats and 3 boys, 3 girls.
First seat can be given to either boy or a girl.
So there are two ways.
If a boy is selected say, then he has to occupy 3rd and 5th only.
There are 2 ways
Now available positions are 2nd, 4th and 6th, in this girls can be arranged in 3! ways = 6
So total number of ways =
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Answer:
7
Step-by-step explanation:
Let’s think about this like a number line.
If we have a number line with the ends of F and H, and G is somewhere in between, it would look something like this.
F———-G———H
We know that FH = 19 and that FG is 12.
This means that GH will be the FH - FG
So FG is 7.
Hope this helped!