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iris [78.8K]
3 years ago
5

Please please help me

Mathematics
2 answers:
IgorLugansk [536]3 years ago
4 0
1. 8.75
2. 2
3.5+4.5= 9.5
motikmotik3 years ago
4 0

Answer:

  1. 5 or 5.5
  2. 4
  3. 7 or 7.5

Step-by-step Explanation:

there isn't much to it

  1. to find the drink... if 6 cartons cost 3 pounds you want to find the ratio so in this case it's 2:1 you can buy 2 drinks with every pound. if you have 2 pounds that's 2x2=4
  2. to find the cakes finding the ratio again... the ratio would be 5:4 and I don't presicely know to find this but i'm guessing the answer would be 5 or 5.5
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In a study of red/green color blindness, 700 men and 2850 women are randomly selected and tested. Among the men, 66 have red/gre
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Answer:

z=\frac{0.0943-0.00281}{\sqrt{0.0208(1-0.0208)(\frac{1}{700}+\frac{1}{2850})}}=15.197  

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If we compare the p value and using any significance level for example \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion of men with red/green color blindness.is significanlty higher than the proportion of women with red/green color blindness.

Step-by-step explanation:

Data given and notation  

X_{M}=66 represent the number of men with red/green color blindness.

X_{W}=8 represent the number of women with red/green color blindness.

n_{M}=700 sample of male slected

n_{W}=2850 sample of female selected

p_{M}=\frac{66}{700}=0.0943 represent the proportion of male with red/green color blindness.

p_{W}=\frac{8}{2850}=0.00281 represent the proportion of female with red/green color blindness.

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportion of men with red/green color blindness. is higher than the proportionof women with red/green color blindness. , the system of hypothesis would be:  

Null hypothesis:p_{M} \leq p_{W}  

Alternative hypothesis:p_{M} > p_{W}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}   (1)

Where \hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{66+8}{700+2850}=0.0208

Calculate the statistic

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.0943-0.00281}{\sqrt{0.0208(1-0.0208)(\frac{1}{700}+\frac{1}{2850})}}=15.197  

Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.  

Since is a one side test the p value would be:  

p_v =P(Z>15.197) \approx 0  

If we compare the p value and using any significance level for example \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion of men with red/green color blindness.is significanlty higher than the proportion of women with red/green color blindness.

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