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3 years ago

Find the exact value of cos(arcsin( one fourth )). For full credit, explain your reasoning. (2 points)

Mathematics

1 answer:

eimsori [14]3 years ago

8 0

Hello from MrBillDoesMath!

Answer:

sqrt(15)/4

Discussion:

The attachment shows a right triangle where arcsin(@) = 1/4. (The arcsin means find the angle whose sine is 1/4 as is done in the triangle.) The missing side, sqrt(15), shown in red, was determined by the Pythagorean theorem.

Then cos(@) = cos(arcsin(1/4)) = sqrt(15)/4

Thank you,

MrB

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In the

muminat

Answer:

72°

Step-by-step explanation:

4+2+6+8=20

360÷20=18

AC=4x18=72

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2 years ago

What is the exact circumference of a circle with a radius of 17 millimeters?

anzhelika [568]

The equation of a circumference is 2 $\pi$ r. Since we know that r=17, we plug that into the formula, and get an answer of C. 34

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2 years ago

Read 2 more answers

What is the answer for this Problem?

geniusboy [140]

Answer:

Increasing on the interval(s) $-2\leq x\leq -4$

Decreasing on the interval(s) $-1\leq y\leq 1$

Step-by-step explanation:

Anytime the graph is going upward, the function is increasing. However, anytime the graph goes down, the function is decreasing. Look at the image below for further reference. Also, when the function is increasing, the slope is positive, and when the function is decreasing the slope is negative.

The increasing interval of the graph is -3

The decreasing interval of the graph is 0.5

Since the values are in the middle of the interval, it automatically becomes the answer.

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2 years ago

Write the definition of a function minmax that has five parameters. the first three parameters are integers. the last two are se

Nitella [24]

Hello,

function minmax(int p1,int p2,int p3, int adr_big, int adr_small)
{ int mini=p1,maxi=p1;
if (p1>p2) {mini=p2;}
else {maxi=p2;};

if (p3>maxi) maxi=p3;
if (p3<mini) mini=p3;
*adr_big=maxi;
*adr_small=mini;
};

// main
int a=31,b=5,c=19,big,small;
minmax(a,b,c,&big,&small);

8 0

3 years ago

Can someone help me with these please?

saul85 [17]

Point-slope form: y-y1 = m(x-x1)

Standard form: ax + by = c

Slope-intercept form: y = mx+b

Start by finding the slope. We know it is negative since the line is decreasing. The slope is -4/3.

To create point-slope form, we need to get one point from the graph. Let's use (3,0).

$y = -\frac{4}{3}(x-3)$

To create slope-intercept form, we need the slope and the y-intercept. The y-intercept is the point where our equation crosses the y-axis. For this equation, it is 4.

$y = -\frac{4}{3}x + 4$

To get standard form, solve the equation in terms of C.

Point-slope form: y = -4/3(x-3)

Slope-intercept form: y = -4/3x + 4

Standard form: 4/3x + y = 4

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3 years ago