Answer:
(x-10)(x+10)
Step-by-step explanation:
Here, the given expression,


By using the identity 

( By the commutative property )
Since, further factorization is not possible,
Hence, the factors of
are,

Second option is correct.
Answer:
The giraffe will be 2 inches
Step-by-step explanation:
If we know that if the scale is 1/2 inch to 5 feet we simply just have to divide the height of the giraffe by 5 feet and then multiply it by 1/2 inches. So we do...
20feet / 5 feet x 1/2 inches = 4 x 1/2inches = 2 inches
All you need to do is pi * radius squared
Answer:
C. The data are qualitative because they don't measure or count anything.
Step-by-step explanation:
Quantitative data is about numbers or counts. For example, the number of children of a couple is an example of quantitative data.
Qualitative data is about characteristics, when they don't count or measure anything. For example, if my favorite kind of movie is comedy, for example, it is an example of qualitative data. There are no counts or measurements.
So the correct answer is:
C. The data are qualitative because they don't measure or count anything.
Answer:
No you cannot.
Step-by-step explanation:
Let c be the amount of time it takes each machine to make 1 cockpit, and p be the amount of time it takes each machine to make 1 propulsion system.
For Machine A, we have 4 cockpits; this would take 4c time. We also have 6 propulsion systems; this would take 6p time. Together it takes 26 hours; this would give us
4c+6p=26.
For Machine B, we have 8 cockpits; this would take 8c time. We also have 12 propulsion systems; this would take 12p time. Together it takes 56 hours; this would give us
8c+12p=56
This gives us the system

To solve this, we want the coefficients of one of the variables to be the same. To make the coefficients of c the same, we can multiply the top equation by 2:

To cancel c, we will subtract the second equation from the first one. However, this also cancels p:

We get a statement that is not true; thus the system has no solution, and we cannot solve for a unique amount of time.