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madreJ [45]
3 years ago
9

Which is the equation of an asymptote of the hyperbola whose equation is

Mathematics
2 answers:
Makovka662 [10]3 years ago
6 0

Answer:C  y=3x-5

Step-by-step explanation:

just took the review test on edg

goldfiish [28.3K]3 years ago
4 0

Answer:

C. y = 3x - 5

Step-by-step explanation:

Given the general equation of a hyperbola:

\frac{(x-h)^{2} }{a^{2}}-\frac{(y-k)^{2} }{b^{2}}=1

The equation for the asymptote line is given by:

y=k+\frac{b}{a} (x-h)

In your problem, we have

\frac{(x-2)^{2} }{4}-\frac{(y-1)^{2} }{36}=1

we have:

h=2,

k=1

a²=4 --> a=2,    im just taking the squareroot

b²=36 --> b=6

put it into your equation

y=k+\frac{b}{a} (x-h)

y=1+\frac{6}{2} (x-2)

y = 1 + 3(x-2)

y = 1 + 3x - 6

y = 3x - 5

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sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

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∂(x, y) /∂(r, θ) =  δx/δθ × δy/δr - δx/δr × δy/δθ

= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

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3 years ago
In a diagram, X is the midpoint of Segment VZ. VW =5, and VY =20. Find the coordinates of W,X, and Y.
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x(5,0)\\
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a_{w}-(-12)=5\\
a_{w}+12=5\\
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w(-7,0)\\
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