Question

What is the solution of the system of equations below?

Answer 1

Answer:

the answer is B  (2,1)

Step-by-step explanation:

Given the simultaneous equation

$2x+3y=7 .....1\\x+y=3 ..........2$

Using substitution method

from equation 2 :

$x=3-y ....3$

Substitute equation 3 into 1:

$2(3-y)+3y=7$

Open the bracket

$2(3)-2y+3y=7\\6-2y+3y=7\\6+y=7\\y=7-6\\y=1$

Substitute y=1 into x=3-y

$x=3-1\\x=2$

Hence the solution to the equation is (2,1)

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