The equation of a horizontal line is y=value<span>. The slope of a horizontal line is </span>0<span>. The y-coordinate of every point on the graph of a horizontal line is </span>value (y=value)<span>. The equation of a vertical line is </span>x=value<span>. The slope of a vertical line is </span>undefined<span>. The x-coordinate of every point on the graph or vertical line is </span>value (x=value).
The general form of the equation of a line isax+by=c<span>. Every line has an equation that can be written in </span>slope-intercept form. When a graphing utility is used to sketch a straight line, the graph of the line may not visually appear to have the slope indicated by its equation because <span>the tick marks are not equally spaced</span>
2x-y=4 minus 2x from both sides -y=-2x+4 times -1 y=2x-4 slope=2 yint=-4
equation of horizontal line is y=value
slope=rise/run, so rise is 0 and run is inifnity so 0 is slope
ycoordinate oof every point of a horizontal ine is the value above mentioned (value)
equation of vertical line is x=value
slope is rise/run, since run=0, it is infinity/0 which is undefined, slope=undefined
xcoordinate is equalt to the value (x=value)
general form of the equation of a line is y=mx+b or ax+by=c every line has an equation that can be writeen in slope-intercept form
the line may not visually appear to have the slope indecated because somethimes the tick marks are not equal distance (use square viewer)
Determine the slope and y-intercept of the linear equation 2x - y = 4 2
The equation of a horizontal line is y=value. The slope of a
horizontal line is 0. The y-coordinate of every point on the
graph of a horizontal line is value (the one from y=value). The equation of a vertical
line is x=value. The slope of a vertical line is undefined.
The x-coordinate of every point on the graph or vertical line is value (x=value). The general form of the equation of a line is ax+by=c. Every line has an equation that can be written in slope-intercept form. When a graphing utility is used to sketch a straight
line, the graph of the line may not visually appear to have the slope
indicated by its equation because the tick marks are not equally spaced
To calculate for area given the circumference we proceed as follows: C=2πr where: r=radius thus given that C=25 1/7 in=176/7 thus plugging in our formula to solve for r we get: 176/7=2πr thus r=4.002~4.00 in hence the area will be: A=πr² A=π×(4²) A=50 2/7 in²
