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iren2701 [21]
3 years ago
14

In the standard (x,y) coordinate plane a right triangle has vertices at (-3,4)(3,4)(3,-4) what is the length in coordinates unit

s of the hypotenuse of this triangle
Mathematics
1 answer:
MAXImum [283]3 years ago
6 0

Given:

The vertices of a right triangle are:

(-3,4),(3,4),(3,-4)

To find:

The length of the hypotenuse of the given right triangle.

Solution:

Let the vertices of the right triangle are A(-3,4),B(3,4),C(3,-4).

The distance formula is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

AB=\sqrt{(3-(-3))^2+(4-4)^2}

AB=\sqrt{(3+3)^2+(0)^2}

AB=\sqrt{(6)^2+0}

AB=\sqrt{36}

AB=6

Similarly,

BC=\sqrt{(3-3)^2+(-4-4)^2}

BC=\sqrt{(0)^2+(-8)^2}

BC=\sqrt{64}

BC=8

And,

AC=\sqrt{(3-(-3))^2+(-4-4)^2}

AC=\sqrt{(6)^2+(-8)^2}

AC=\sqrt{36+64}

AC=\sqrt{100}

AC=10

Now, taking sum of squares of two smaller sides, we get

AB^2+BC^2=6^2+8^2

AB^2+BC^2=36+64

AB^2+BC^2=100

AB^2+BC^2=AC^2

By the definition of the Pythagoras theorem, AC is the hypotenuse of the given triangle.

Therefore, the length of the hypotenuse is 10 units.

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