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SVEN [57.7K]
3 years ago
6

One of the solutions to x2 − 2x − 15 = 0 is x = −3. What is the other solution?

Mathematics
2 answers:
svet-max [94.6K]3 years ago
6 0
<span>x2 − 2x − 15 = 0
</span>(x+3)(x-5) = 0
x +3 = 0 so x = -3
x - 5 = 0 so x = 5

answer is <span>d.x = 5</span>
denis23 [38]3 years ago
6 0

Answer:

x=5

Step-by-step explanation:

One of the solutions to x^2 - 2x - 15 = 0 is x = −3

To find out the other solution, we factor the x^2-2x-15

Product is -15 and sum is -2

-5 \cdot 3 = -15

-5+3= -2

So factors are -5 and 3

x^2 - 2x - 15 = 0

(x-5)(x+3)= 0

we set each factor =0 and solve for x

x-5=0, x=5

x+3=0, x=-3

other solution is x=5

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To proof

As given in the question

Let us assume that the number of hours charged at the day rate = d

Let us assume that the number of hours charged at the night rate = n

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d + n = 12

also

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Aleksandr-060686 [28]

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