Mid point of countinious AB if A=(-2,2) and B = (3,-1)
2 answers:
-2+3= -1/2
2+(-1)= 2-1= 1
Midpoint= (-1/2, 1)
The formula is (x1+x2)/2, (y1+y2)/2
Remark
The midpoint of any line has a definite formula. All you need do is define the formula parts in terms of the points.
Formula
x = (x1 + x2)/2
y = (y1 + y2)/2
Givens
x1 = -2
x2 = 3
y1 = 2
y2 = -1
Solution
x = (-2+3)/2 = 1/2
y = (2 + -1)/2 = 1/2
Answer
The midpoint is (1/2,1/2)
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