Question

Suppose that the population of a town Increases by 3% each year. the population of the town today is 25,000

Answer 1

Answer:

The population of town after 1 year is 25,750  .

Step-by-step explanation:

Given as :

The rate of increase in the population of town each year = 3 %

The initial population of town = 25,000

Let the population of town after one year = x

So,

The population after n year = initial population × $(1+\dfrac{\textrm rate}{100})^{\textrm n}$

Or, The population after 1 year = 25,000 × $(1+\dfrac{\textrm 3}{100})^{\textrm 1}$

Or, The population after 1 year = 25,000 × $(1.03)^{1}$

Or,  The population after 1 year = 25,000 × 1.03

∴  The population after 1 year = 25,750

Hence The population of town after 1 year is 25,750  . Answer