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Nataly [62]
3 years ago
8

Can someone pls help

Mathematics
1 answer:
tatuchka [14]3 years ago
5 0

Answer:

Step-by-step explanation:

It's not that clear on my screen

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What’s 2 + 2? <br> A. 0<br> B. 1<br> C. 2<br> D. 4
snow_tiger [21]

Answer:

are u kidding me it's literally D --_--

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Solve the system of equations.
Xelga [282]

Answer:

  b.  x=1, y=2, z=3

Step-by-step explanation:

The system of equations ...

  • 3x +2y +z = 10
  • 9x -6y +z = 0
  • x -y -3z = -10

has solution (x, y, z) = (1, 2, 3) . . . . matches choice B.

_____

While it is convenient to solve this using a graphing calculator or web site, one can easily solve the system by hand.

Subtract the second equation from 3 times the first:

  3(3x +2y +z) -(9x -6y +z) = 3(10) -(0)

  12y + 2z = 30 . . . . simplify

Dividing this result by 2 gives ...

  6y +z = 15 . . . . . . [eq4]

Subtract 3 times the third equation from the first:

  (3x +2y +z) -3(x -y -3z) = (10) -3(-10)

  5y +10z = 40 . . . . simplify

  y + 2z = 8 . . . . . . . divide by 5 . . . . . [eq5]

The two equations [eq4] and [eq5] can be solved any of the ways you usually solve two equations in two variables. Here, we'll use the first equation to write an expression for z that we can substitute into the second equation.

  z = 15 -6y . . . . . subtract 6y from [eq4]

  y + 2(15 -6y) = 8 . . . . . substitute for z in [eq5]

  -11y +30 = 8 . . . . . simplify

  -11y = -22 . . . . . . . subtract 30

  y = 2 . . . . . . . . . . . divide by the coefficient of y

  z = 15 -6(2) = 3 . . . . substitute for y in our equation for z

Substituting these values for y and z into the third original equation gives ...

  x - 2 -3(3) = -10

  x -11 = -10 . . . . . . . . simplify

  x = 1 . . . . . . . . . . . . add 11

The solution to the above system of equations is (x, y, z) = (1, 2, 3).

_____

<em>Comment on the problem statement</em>

Math is generally unforgiving of imprecision. The given system of equations has no variable "z", and some other typos are apparently involved. That is why we rewrote the system to the equations shown above.

It is very easy to mistake z for 2, or g for 9, or o for 0, or 1 for 7. There are other confusions that are possible, as well. Letters I (eye) and l (ell) are easily confused, and may be confused with 1 (one) as well. Sometimes y and 4, or 4 and 9, can also be written so as to be difficult to tell apart. Great care must be taken when handwriting these symbols.

7 0
3 years ago
What is the solution to the system of equations?
alukav5142 [94]

Answer:

  (x, y) = (-4, 15)

Step-by-step explanation:

The two equations have the same coefficient for y, so you can eliminate y by subtracting one equation from the other. Here the x coefficient is largest for the first equation, so it will work best to subtract the second equation.

  (3x +y) -(2x +y) = (3) -(7)

  x = -4 . . . . . . . . simplify

Now, we can find y by substituting this value for x.

  2(-4) +y = 7

  y = 7 +8 = 15 . . . . . add 8 to both sides of the equation

The solution is (x, y) = (-4, 15).

6 0
3 years ago
Write down and simplify the following algebraic expressions. The sum of −3x+5 and 7−4x is subtracted from 5x+17.
andriy [413]
Sum of the first two is:
-3x+5+7-4x = -7x+12
That subtracted from 5x+17:
5x+17-(-7x+12) = 12x+5
5 0
3 years ago
Applying Properties of Exponents In Exercise, use the properties of exponents to simplify the expression.
NemiM [27]

Answer: (a) e^3

(b) e^{10}

(c) \dfrac{1}{e^4}

(d) e^{4}

Step-by-step explanation:

Properties of exponents :

1) a^m\times a^n=a^{m+n}

2) \dfrac{a^m}{a^n}=a^{m-n}

3) (a^m)^n=a^{mn}

4) a^{-n}=\dfrac{1}{a^n}

Now , we simplify the given expression using the above properties.

a) (e^6)(e^{-3})

=e^{6+(-3)}   [By property (1)]

=e^{6-3}=e^3  [∵ (+)(-)=(-)]

b) (e^{-2})^{-5}

=e^{-2\times-5}  [By property (3)]

=e^{10}   [∵ (-)(-)=(+)]

c) (\dfrac{e^6}{e^2})^{-1}

=(e^{6-2})^{-1}    [By property (2)]

=(e^{4})^{-1}  

=\dfrac{1}{e^4}       [By property (4)]

d) (e^3)^{\frac{4}{3}}

=e^{3\times\frac{4}{3}}        [By property (3)]

=e^{4}  

7 0
3 years ago
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