To calculate minimum value, do -b/2a to get the x-value, and plug it in to get the y-value:
-6/8 = -3/4
So the minimum value of g(x) is -81/4
This shows that g(x) has a lesser minimum value than f(x)
A. 
is the secant line on the below circle.
<u>Step-by-step explanation:</u>
The intersection of the circle will result in either Tangent or Secant. Secant is a line intersecting a circle at two different point. This concept explains the relation between the circle and line intersecting it.
From the given diagram,
The 
and 
intersects the circle at the point H and I.
∴ It can also represented that the 
and intersects at a point G.
From the given options is the secant line that intersects the circle twice.
-m
One times itself but as a negative.
Answer:
8
Step-by-step explanation:
Reduce the fraction to 1/2 then multiply it by 8 which is 8:) this this helps! Plzz mark brainliest
The required Comparison of the inequalities are
- The |x – 1| + 1 > 15 represents the value of x lies between 13<x<15.
The range of values encompassing the region's junction is (-13, 15).
- If x is more than or equal to 15, then x-11+1>15 indicates the value of x is greater than or equal to 13. None of the regions in the intersection are empty.
<h3>What is inequality?</h3>
When comparing two numbers, an inequality indicates whether one is less than, larger than, or not equal to the other.
We take into account the various variables of the inequality
|x – 1| + 1 > 15
Therefore
|-x-1|+1-1<15-1
|-x-1|-1 <14
13<x<15
The required region lies between the inequality -13 <x< 15.
Simplify the inequality Ix-11+1 > 15 we get,
|x-1|+1 > 15
|x+1| +1-1 >15-1
|x-1| > 14
x> 15
x<-13
- If x has a value between -13 and x + 15, then the expression "|x-1|+1+115" is true. The range "(-13, 15)" contains the intersection of the region.
- If "|x-1|+1>15" then either "x >15" or "x-13" applies to the value of x. This region's intersection is unoccupied.
Read more about inequalities
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