Answer:
The histogram for the data is attached below.
Step-by-step explanation:
The methods commonly used for depicting a frequency distribution are:
- Histogram/Column graph
- Bar graph
- Frequency Polygon
- Pie chart
Out of these, one of the most general and extensively used devices of illustrating a frequency distribution is the histogram.
The data provided for the number of tunnels Gary the groundhog dug each year is:
S = {18, 5, 13, 9, 6, 2, 10}
The histogram for the data is attached below.
Answer:
d. Variable ratio
Step-by-step explanation:
We are asked to determine that gambling at a slot machine is an example of which reinforcement schedule.
Let us see our given choices one by one.
a. Fixed ratio
We know that in fixed ratio schedule, reinforcement is delivered after the completion of a number of responses. An example of fixed ratio is a reward to every 6th response.
b. Fixed interval
We know that in fixed interval schedule the first response is rewarded only after a specified amount of time has elapsed. An example of fixed interval schedule is weekly paycheck.
c. Variable interval
We know that in variable interval schedule, the reinforcement is delivered at changing and unpredictable intervals of time.
d. Variable ratio
In variable ratio schedule, a response is reinforced after an unpredictable number of responses. Gambling and lottery are examples of variable ratio.
Therefore, option 'd' is the correct choice.
<span>Acceleration of a passenger is centripetal acceleration, since the Ferris wheel is assumed at uniform speed:
a = omega^2*r
omega and r in terms of given data:
omega = 2*Pi/T
r = d/2
Thus:
a = 2*Pi^2*d/T^2
What forces cause this acceleration for the passenger, at either top or bottom?
At top (acceleration is downward):
Weight (m*g): downward
Normal force (Ntop): upward
Thus Newton's 2nd law reads:
m*g - Ntop = m*a
At top (acceleration is upward):
Weight (m*g): downward
Normal force (Nbottom): upward
Thus Newton's 2nd law reads:
Nbottom - m*g = m*a
Solve for normal forces in both cases. Normal force is apparent weight, the weight that the passenger thinks is her weight when measuring by any method in the gondola reference frame:
Ntop = m*(g - a)
Nbottom = m*(g + a)
Substitute a:
Ntop = m*(g - 2*Pi^2*d/T^2)
Nbottom = m*(g + 2*Pi^2*d/T^2)
We are interested in the ratio of weight (gondola reference frame weight to weight when on the ground):
Ntop/(m*g) = m*(g - 2*Pi^2*d/T^2)/(m*g)
Nbottom/(m*g) = m*(g + 2*Pi^2*d/T^2)/(m*g)
Simplify:
Ntop/(m*g) = 1 - 2*Pi^2*d/(g*T^2)
Nbottom/(m*g) = 1 + 2*Pi^2*d/(g*T^2)
Data:
d:=22 m; T:=12.5 sec; g:=9.8 N/kg;
Results:
Ntop/(m*g) = 71.64%...she feels "light"
Nbottom/(m*g) = 128.4%...she feels "heavy"</span>
Answer:
1) 144
2) 1
Step-by-step explanation:
Answer:
72
Step-by-step explanation:
8 times 9 is 72
