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PIT_PIT [208]
3 years ago
14

What is the decimal 0.84 (84 repeating) as a fraction? Help pretty please

Mathematics
1 answer:
mr_godi [17]3 years ago
4 0

Answer:

28/33

Step-by-step explanation:

We first let 0.84 be  x.

Since  x  is recurring in 2 decimal places, we multiply it by 100.

100x=84.84

Next, we subtract them.

100x−x=84.84−0.84

99x=84

Lastly, we divide both sides by 99 to get  x  as a fraction.

x=84/99

=28/33

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Translate this sentence into an equation.
motikmotik

Answer:

g = 61.

Step-by-step explanation:

g + 9 = 70             Subtract 9 from both sides of the equation:

g + 9 - 9 = 70 - 9

g = 61.

4 0
3 years ago
• How do you write the mixed number shown as a fraction greater than l? 3 4​
Firdavs [7]

Answer:

\frac{14}{4}

simplified \frac{7}{2}

Step-by-step explanation:

To turn a mixed number into a fraction :

3\frac{ + 2}{ \times 4}

3 x 4 =12 +2 =14 that will be your numerator (top number on a fraction)

and 4 will be your demoninator (bottom number)

8 0
2 years ago
Select the equivalent expression. <br><br> A, B or C?
Alina [70]

Answer:

  A

Step-by-step explanation:

The relevant rules of exponents are ...

  (a^b)^c = a^(bc)

  a^-b = 1/a^b

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  \left(\dfrac{2^{-10}}{4^2}\right)^7=\dfrac{2^{(-10)(7)}}{4^{(2)(7)}}=\dfrac{2^{-70}}{4^{14}}\\\\=\boxed{\dfrac{1}{2^{70}\cdot 4^{14}}}

6 0
3 years ago
Dan painted 3/4 of a wall using 1/4 of a can of paint.Select all statements that are true.
Juli2301 [7.4K]

Answer:

  B, C, F

Step-by-step explanation:

3/4 is 3 times 1/4, so the number of walls Dan can paint is 3 times the number of cans Dan uses.

A. 1/2 can will paint 3/2 walls, not 2.

B. 1 can will paint 3 walls — true

C. 5/3 cans will paint 5 walls — true

D. 2 cans will paint 6 walls, not 8.

E. 5/2 cans will paint 15/2 = 7 1/2 walls, not 10.

F. 11/3 cans will paint 11 walls — true

5 0
3 years ago
Suppose x=c1e−t+c2e3tx=c1e−t+c2e3t. Verify that x=c1e−t+c2e3tx=c1e−t+c2e3t is a solution to x′′−2x′−3x=0x′′−2x′−3x=0 by substitu
Harrizon [31]

The correct question is:

Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)

Answer:

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

Step-by-step explanation:

We need to verify that

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

We differentiate

x = c1e^(-t) + c2e^(3t)

twice in succession, and substitute the values of x, x', and x'' into the differential equation

x''- 2x' - 3x = 0

and see if it is satisfied.

Let us do that.

x = c1e^(-t) + c2e^(3t)

x' = -c1e^(-t) + 3c2e^(3t)

x'' = c1e^(-t) + 9c2e^(3t)

Now,

x''- 2x' - 3x = [c1e^(-t) + 9c2e^(3t)] - 2[-c1e^(-t) + 3c2e^(3t)] - 3[c1e^(-t) + c2e^(3t)]

= (1 + 2 - 3)c1e^(-t) + (9 - 6 - 3)c2e^(3t)

= 0

Therefore, the differential equation is satisfied, and hence, x is a solution.

4 0
2 years ago
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