Answer:
I. Viewing many television programs that associate successful males with football
III. Operant conditioning
IV. Gender schemata
Explanation:
As we can see in the question above, the boy contracted a very wrong custom of associating virility with his ability and taste for playing football. According to the boy, he is only manly and manly enough boys who like and know how to play football.
This thought (which is extremely wrong) occurs with the influence of some things. The first is the frequency with which this boy watches many television programs that show men, soccer players with a successful and well-established career.
The second influence is the result of operant conditioning, which is a psychological concept characterized by a form of learning that allows a person to associate a situation with a punishment. In this case, the boy associates the lack of skill and the lack of interest in football with words that cause embarrassment as punishment. For this reason, he calls his colleagues who don't like football "sissy".
The third influence occurs through gender schemes, which is a term used to describe the separation of things, activities and behavior as feminine and masculine, in addition to determining that only women can do what is considered feminine and only men can do what it's male. The boy associates football with masculinity and those who do not like or have no interest in football are feminine, effeminate and not men.
The correct answer is the semantic level of encoding.
When you are trying to memorize something using semantic encoding, it means that you are using tools such as mnemonics to better learn information and retrieve it from memory more easily. Semantics has to do with language, meaning, and words.
<span>The "product line" rule must be used to find out the number of ways that two representatives can be picked so that one is a mathematics major and the other is a computer science major.
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The product line states that if the two functions f(x) and g(x) are differentiable (i.e. the derivative exist) then the product is differentiable and:
(fg)'=f'g+fg'
