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Cloud [144]
4 years ago
5

Honey and Money are twin brothers. Mother wants to equally divide a rectangular shaped cake of 5cm wide and 6cm long. Find the l

ength of the third cake, if it were cut diagonally.

Mathematics
1 answer:
tatuchka [14]4 years ago
5 0

Answer:

Length of rectangular cake = 5 cm

Breadth of rectangular cake = 6 cm

Area of rectangle = 5 cm × 6 cm =30 cm²

If cake is equally distributed between Honey and Money, then areas of two parts should be equal.

So, Amount of cake that Honey and money got \frac{30}{2}=15

Share of each (Honey and Money)=15 cm²

So, if the third cake if it was cut diagonally ,the cake must have some height.

Let the height of cake be H.

So, Height of third cake =\sqrt{L^2+B^2+H^2}\\\\=\sqrt{5^2+6^2+H^2}\\\\=\sqrt{61+H^2}

If , H=0 that is height is negligible having 0 thickness,

Then the Length of third cake, which is divided into two parts=√61=7.81 cm

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The solution to 5 - 3x> 35 is either x>-10 or -10> x. which solution is correct
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It should be x < -10 because when you divide by a negative number the inequality sign flips.

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Macy is painting a design that contains two repeating patterns. One pattern repeats every 8 inches. The other repeats every 12 i
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4 years ago
Consider the equation y = 3x - 1. Identify the slope and y-intercept and
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Answer: slope=3

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4 0
3 years ago
The circumference of a sphere was measured to be 80 cm with a possible error of 0.5 cm. A) Use differentials to estimate the max
siniylev [52]

Answer:

A) The maximum error in the calculated surface area: 25cm^2

Relative error: 0.013

B) The maximum error in the calculated volume: 162cm^2

Relative error: 0.019

Step-by-step explanation:

A) The formula for the surface area is:

A=4\pi r^2

The measured value is the circumference which is equal to:

C=2\pi r

then the radius is:

r=\frac{C}{2\pi}

Substituting in the formula of the surface:

A=4\pi(\frac{C}{2\pi})^2\\A=4\pi(\frac{C^2}{4\pi^2})\\A=\frac{C^2}{\pi}

Using the formula to calculate the error:

dy=f'(x)dx

Where x is the variable measured and y is a function of x(y=f(x)).

dA=f'(C)dC\\dA=\frac{2C^{(2-1)}}{\pi}dC\\dA=\frac{2C}{\pi}dC

We have C=80cm and dC=0.5cm

dA=\frac{2C}{\pi}dC\\dA=\frac{2(80)}{\pi}(0.5)\\dA=\frac{160}{\pi}(0.5)\\dA=50.9296(0.5)\\dA=25.4648\approx25cm^2

The relative error is the maximum error divide by the total area. The total area is: A=\frac{C^2}{\pi}=\frac{(80)^2}{\pi}=\frac{6400}{\pi}=2037.1833cm^2

\frac{dA}{A}=\frac{25.4648}{2037.1833} =0.0125\approx0.013

B) The formula for the volume is:

V=\frac{4}{3} \pi r^3

Using r=\frac{C}{2\pi}

V=\frac{4}{3} \pi r^3\\V=\frac{4}{3} \pi (\frac{C}{2\pi})^3\\V=\frac{4}{3} \pi (\frac{C^3}{8\pi^3})\\V=\frac{1}{3}(\frac{C^3}{2\pi^2})\\V=\frac{C^3}{6\pi^2}

The maximum error is:

dV=\frac{3C^{3-1}}{6\pi^2}dC\\dV=\frac{C^{2}}{2\pi^2}dC\\dV=\frac{(80)^{2}}{2\pi^2}(0.5)\\dV=\frac{6400}{2\pi^2}(0.5)\\dV=\frac{6400}{2\pi^2}(0.5)\\dV=(324.2278)(0.5)\\dV=162.1139\approx162cm^2

The calculated volume is:

V=\frac{C^3}{6\pi^2}\\V=\frac{(80)^3}{6\pi^2}\\V=\frac{512000}{6\pi^2}\\V=8646.0743

The relative error is:

\frac{dV}{V}=\frac{162.1139}{8646.0743}=0.0188\approx0.019

3 0
3 years ago
(100 points if answered) (attatched screenshot) Algebra II need question 1 and 2
Elanso [62]
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3 0
3 years ago
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