Question

Square EFGH stretches vertically by a factor of 2.5 to create square E′F′G′H′. The square stretches with respect to the x-axis. If point H is located at (-2, 0), what are the coordinates of H?
A.(-5, 0)
B.(-2, 0)
C.(0.5, 0)
D.(-2, 2.5)

Answer 1

Square EFGH stretches vertically by a factor of 2.5 to create square E′F′G′H′. The square stretches with respect to the x-axis. If point H is located at (-2, 0), the coordinates of H will be at point "D.(-2, 2.5)." Since it stretches vertically, it assumed that it stretches all parallel with the y axis.

Answer 2

Answer with explanation:

Pre -image= Square E F G H

Image=Square E′F′G′H′

Vertical Stretch Factor= 2.5

Coordinates of Point H= (-2,0)

If, (x,y), is the coordinate of any point, and , m is vertical stretch factor,then coordinate of Image =(x, my)

→Here, Vertical stretch, factor is 2.5,and coordinates of H=(-2,0) then Coordinates of H' will be =(-2, 0×2.5)=(-2,0)

Option B: (-2,0)