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elena-s [515]
3 years ago
15

Before paying employee bonuses and state and federal taxes, a company earns profits of $103,000. The company pays employees a bo

nus equal to 5% of after-tax profits. State tax is 5% of profits (after bonuses are paid). Finally, federal tax is 40% of profits (after bonuses and state tax are paid). Calculate the amounts paid in bonuses, state tax and federal tax.
Mathematics
1 answer:
mamaluj [8]3 years ago
4 0

Answer:

The amounts paid in bonuses, state tax and federal tax is $ 2,855, $ 5008 and $ 38,055 respectively.

Step-by-step explanation:

This problem requires us to calculate the amounts paid in bonuses, state tax and federal tax. We can solve this problem with the help of math’s equation given below.

Let x be the amount of bonus than

x = 5% (103,000- x- 5% (103,000-x)- 40%(103,000- x- 5% (103,000-x)))

x = 0.05 (103,000 -x - 5,150 + 0.05x -41,200 + 0.4x + 2,060 - 0.02x)

x = 0.05 (58,710 - 0.57x)

x = 2,935.5 - 0.0285x

x = $ 2,855

State Tax = (103,000 -2,855)*5% = $ 5008

Federal tax = (103,000-2,855- 5,008) * 40% = $ 38,055

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Please help with a, b, and c!!
padilas [110]
(a). 
The product of two binomials is sometimes called FOIL.
It stands for ...

       the product of the First terms                (3j  x  3j)
plus
       the product of the Outside terms          (3j  x  5)
plus
       the product of the Inside terms            (-5  x  3j)
plus
       the product of the Last terms                (-5  x  5)

FOIL works for multiplying ANY two binomials (quantities with 2 terms).

Here's another tool that you can use for this particular problem (a).
It'll also be helpful when you get to part-c .

Notice that the terms are the same in both quantities ... 3j and 5 .
The only difference is they're added in the first one, and subtracted
in the other one.

Whenever you have     

              (the sum of two things) x (the difference of the same things)

the product is going to be

                 (the first thing)²  minus  (the second thing)² .

So in (a), that'll be      (3j)² - (5)²  =  9j² - 25 .

You could find the product with FOIL, or with this easier tool.
______________________________

(b).
This is the square of a binomial ... multiplying it by itself.  So it's
another product of 2 binomials, that both happen to be the same:

                            (4h + 5) x (4h + 5)  .

You can do the product with FOIL, or use another little tool:

The square of a binomial        (4h + 5)²    is ...

         the square of the first term               (4h)²
plus
         the square of the last term                (5)²
plus
         double the product of the terms      2 · (4h · 5)
________________________________

(c).
Use the tool I gave you in part-a . . . twice .

The product of the first 2 binomials is           (g² - 4) .

The product of the last 2 binomials is also    (g² - 4) .

Now you can multiply these with FOIL,
or use the squaring tool I gave you in part-b .

5 0
3 years ago
Read 2 more answers
Victoria has $2.90 in quarters, dimes and nickels. The numbers of nickels is one more than six times the number of quarters, and
maria [59]

Answer:

Step-by-step explanation:

She has 290 cents.

Nickels: 6x+1

Quarters: x

Dimes: 4x

Now that we've converted it algebraically, we can add them

6x+1 + x + 4x = 11x+1 = 290

11x = 289

x = 289/11

let me know if incorrect, i will fix

8 0
3 years ago
I need this one solved Chief.
nikdorinn [45]
X is equal to 8
Y is equal to 0
4 0
3 years ago
Suppose that a group of 10 students are to be assigned to four dorm rooms: a single, a double, a triple and a quad. How many way
Nesterboy [21]

Answer:

Total number of ways to select all sstudent to make assignment = 10×36×70×1 = 25200

Step-by-step explanation:

We have given number of students = 10

These 10 students are assigned to four dorm rooms a single, a double, a triple and a quad

So number of ways to assigned single student =^{10}C_1=\frac{10!}{1!9!}=10\\

Now left student = 10 -1 = 9

So number of ways to assigned double student =^{9}C_2=\frac{9!}{2!7!}=36

Now left student = 9-2 = 7

So number of ways to assigned triple student =^{7}C_3=\frac{7!}{2!4!}==70

Now left student = 7 - 3 = 4

So number of ways to assigned quad student =^{4}C_4=\frac{4!}{4!0!}=1

So total number of ways to select all sstudent to make assignment = 10×36×70×1 = 25200

6 0
3 years ago
What is the √ 100 / 4x squared
Sholpan [36]

Answer:

5/2x^2 or 2.5x^2 I think

4 0
3 years ago
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