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Fittoniya [83]
3 years ago
7

Which expression is equivalent to –2(5x – 0.75)?

Mathematics
2 answers:
vesna_86 [32]3 years ago
5 0

Answer:The answer is D -10x+ 1.5

Step-by-step explanation:Because if you use the distributive property on

-2(5x - 0.5) you multiply -2 by 5x to get -10x then you multiply -2 by -0.5 to get a positive 1.5.

Zinaida [17]3 years ago
3 0

Answer:

5(5x - 0.34

Step-by-step explanation:

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27. Find the unit rate of 1400 words per 20 minutes.
Dominik [7]

Answer:

the rate is 70 words per minutes.

Step-by-step explanation:

1400 ÷ 20 = 70

3 0
3 years ago
Read 2 more answers
The total combined volume of a glass, a jar, and a pitcher is 54 liters. If the jar has the same volume as 3 glasses and the pit
lutik1710 [3]

Answer:

6 liters.

Step-by-step explanation:

So we have a glass, a jar, and a pitcher and together, they hold 54 liters.

We are told that the jar has the same volume as 3 glasses and the pitcher has the same volume as 5 glasses. In other words, let g denote glasses, j denote jars, and p denote pitchers:

g+j+p=54

Since  jar is the same as 3 glasses, this means that j=3g. And since the pitcher is the same as 5 glasses, this means that p=5g. Substitute:

g+(3g)+(5g)=54

Combine like terms:

9g=54

Divide both sides by 9. The left cancels:

(9g)/9=54/9\\g=6

Therefore, the volume of the glass is 6 liters.

7 0
3 years ago
Read 2 more answers
part of the object is a rectangle that is twice as tall it is wide one of the rectangles sides is also a side of a pentagon
VikaD [51]

Answer:

b

Step-by-step explanation:

5 0
3 years ago
Enter an algebraic expression to model the given context. Give your answer in simplest form.
statuscvo [17]

Answer:

p=0.006=1.006

Step-by-step explanation:

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3 years ago
A basketball tosses a ball to a teammate. The ball reaches a maximum height of 11 feet 3 seconds after it was released. If the b
labwork [276]

Answer:

h = - 16t² + 49.67t + 6

Step-by-step explanation:

The expression for the height of the basketball, h at time, t is given by

h - h₀ = u₀t - 1/2gt² where h₀ = initial height of ball = 6 feet, h = maximum height of ball = 11 feet, u₀ = initial vertical velocity of ball, t = time taken to reach maximum height = 3 s and g = acceleration due to gravity =9.8 m/s².

We need to find u₀ from u = u₀ -

So, h - h₀ = u₀t - 1/2gt²

h - h₀ + 1/2gt² = u₀t

u₀ = (h - h₀)/t + 1/2gt

substituting the values of the variables into the equation, we have

u₀ = (h - h₀)/t + 1/2gt

u₀ = (11 ft - 6 ft)/3s + 1/2 × 32 ft/s² × 3 s

u₀ = 5 ft/3s + 1/2 × 96 ft/s

u₀ = 1.67 ft/s + 48 ft/s

u₀ = 49.67 ft/s

Using h - h₀ = u₀t - 1/2gt² where h is the height of the basketball at time, t

h = u₀t - 1/2gt² + h₀

substituting the values of the variables into the equation, we have

h = u₀t - 1/2gt² + h₀

h = (49.67ft/s)t - 1/2(32 ft/s²)t² + 6 ft

h = 49.67t - 16t² + 6

h = - 16t² + 49.67t + 6

3 0
3 years ago
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