Answer: C
Step-by-step explanation:
The line is shaded below and is solid.
This eliminates all the options except for C.
Limit of x approaches two from the left of f of x: 3. Limit of x approaches two from the right of f of x: - 1 (negative 1)
<h3>How to find the value of the
function as x approaches infinity (+ve or -ve)?</h3>
If limits exist, we can take limits of the function, where x tends to -∞ or ∞, and that limiting value will be the value the function will approach.
In order to find the limit as x approaches two from the left of f of x:
Lim x→2- f(x) = ?
According to the graph, when x approaches two from the left (x<2), the function approaches 3:
Lim x→2- f(x) = 3
IN order to find the limit as x approaches two from the right of f of x:
Lim x→2+ f(x) = ?
According to the graph, when x approaches two from the right (x>3), the function approaches -1:
Lim x→2+ f(x) = - 1
Learn more about one-sided limits here:
brainly.com/question/23625942
#SPJ1
Answer:
f(x) = 1/25x² - 1
Step-by-step explanation:
Given that:
The quadratic function f(x) = y = ax² + bx + c
Replace (x,y) = (5,0)
0 = a5² + b5 + c
0 = 25a + 5b + c ---- (1)
The differential eqaution;dt/dx = 2ax + b at (x,y) = (0, -1) it has minimum.
Thus, dy/dx = 0
2ax + b = 0
2a(0) + b = 0
0 + b = 0
b = 0 --- (2)
Now, replace (x,y) = (0, - 1) into equation (1)
Then;
-1 = 0 + 0 + c
c = -1
From equation (1)
0 = 25a + 5(b) + c
0 = 25a + 5(0) + c
c = - 25a
a = - c/25
a = -(-1)/25
a = 1/25
Therefore; the derived quadratic equation:
y = ax² + bx + c
y = 1/25x² + (0)(x) - 1
y = 1/25x² - 1
f(x) = 1/25x² - 1
Answer:
Step-by-step explanation:
= 10 square inches
Area of the place mat = 42 * 10 = 420 square inches
Area of each triangle = 10 square inches
Area of the place mat = 420 square inches