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Answer:
- Constraints: x + y ≤ 250; 250x +400y ≤ 70000; x ≥ 0; y ≥ 0
- Objective formula: p = 45x +50y
- 200 YuuMi and 50 ZBox should be stocked
- maximum profit is $11,500
Step-by-step explanation:
Let x and y represent the numbers of YuuMi and ZBox consoles, respectively. The inventory cost must be at most 70,000, so that constraint is ...
250x +400y ≤ 70000
The number sold will be at most 250 units, so that constraint is ...
x + y ≤ 250
Additionally, we require x ≥ 0 and y ≥ 0.
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A profit of 295-250 = 45 is made on each YuuMi, and a profit of 450-400 = 50 is made on each ZBox. So, if we want to maximize profit, our objective function is ...
profit = 45x +50y
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A graph is shown in the attachment. The vertex of the feasible region that maximizes profit is (x, y) = (200, 50).
200 YuuMi and 50 ZBox consoles should be stocked to maximize profit. The maximum monthly profit is $11,500.
Answer: (a) 10 (b) 1. 10 2. -10 (c) 1. 10 2. 10
Step-by-step explanation:
Since there are 2 semesters per year we have:
(1/2)(24,870 - 7,560) = $8,655
David would have to contribute $8,655 per semester.
Answer:
Width is 10 1/2 inches and the length = 21 inches.
Step-by-step explanation:
Let the width be x then the length us 2x inches.
Perimeter = 2x + 2(2x) = 63
6x = 63
x = 10 1/2 inches.
Answer:
Length = 2x + 5
Width = x + 3
Step-by-step explanation:
Area of rectangle = length × width
Expression for area of the rectangle = 2x² + 11x + 15
Factorising the quadratic expression
2x² + 11x + 15 = 2x² + 6x + 5x + 15 = (2x² + 6x) + (5x + 15) = 2x(x + 3) +5(x + 3) = (2x + 5)(x + 3)
Length = 2x + 5
Width = x + 3