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masya89 [10]
3 years ago
5

What is the square root of 9800 in simplest radical form?

Mathematics
1 answer:
Mumz [18]3 years ago
4 0
The square root of 9800=

= 70 * square root of 2


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Find the area of the region between a regular hexagon with sides of 6" and its inscribed circle.
kirza4 [7]

Answer:

Area of the region = 15.03 in²

Step-by-step explanation:

Area of region between a regular hexagon with sides 6" and circle inscribed.

So Area of region = Area of regular hexagon - area of circle

Now area of regular hexagon = \frac{3a^{2} \sqrt{3}}{2}

where a = side of the hexagon = 6"

Now area of regular hexagon = \frac{3(6^{2})\sqrt{3}}{2}=\frac{108\sqrt{3}}{2} = 93.53 square in.

Area of circle inscribed = πr²

Here r is the radius of the circle = \sqrt{6^{2}-3^{2}}=\sqrt{36-9}

r = 5"

So area of the inscribed circle = π(5)² = 3.14(25) = 78.5 square in.

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Step-by-step explanation:

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Montano1993 [528]

Answer:

<h2>W = -36</h2>

Step-by-step explanation:

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frosja888 [35]

X=105°

Y=105°

Z=105°

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A=105°

X=A[Verticall opposite angle]

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Y=X[alternate angle]

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2 years ago
How do you write numbers without scientific notation
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