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posledela
3 years ago
15

A cylindrical piece of iron pipe is shown below. The wall of the pipe is 0.75 inch thick, and the pipe is open at both ends: The

figure shows a cylinder of height 16 inches and diameter 6 inches. What is the approximate inside volume of the pipe? (8 points) 113 cubic inches 452 cubic inches 410 cubic inches 254 cubic inches
Mathematics
1 answer:
Elodia [21]3 years ago
4 0

Answer: 154 cu. in

Step-by-step explanation:

The space you have to measure is a cylinder.

Its height is the same as the height of the pipe, 16 inches.

Its diameter =inner diameter of pipe

= outer diameter of pipe - thickness of walls at each end of diameter

= 6 - 2(1.25)

= 3.5 inches

radius r = 1.75 inches

A cross-section of the cylindrical space is a circle.

area of circle = πr² = π * 1.75² = 9.625

volume = area of circle * height

9.625 * 16

= 154 cu. in.

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Please help and thank you!
Stolb23 [73]

The conversion is

x =  r \cos \theta

y = r \sin \theta

So

\dfrac y x = \tan \theta

We're given the fairly unusual

\theta = -\frac 5 2

It's fairly unusual because usually an angle is given in degrees or radians, and typically the radians are a fraction times pi. We'll assume radians.

\dfrac y x = \tan \theta = \tan(-5/2) \approx 0.747

Ah, there's our .75. The approximate answer is

y = 0.75 x

Third choice.

The exact answer is

y = x \tan( -\frac 5 2)

also a line through the origin.

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3 years ago
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bagirrra123 [75]

The answer is D) (-1,-12)

Reason:

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2) 2x-10=4x-8

3) -2x-10=-8

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6) substitute -1 for x in y=2x-10

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x=-1 and y=-12

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