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Over [174]
3 years ago
7

Complete the equation 3 to the 2nd power * 3 to the _____ power = 3 to the 10th power

Mathematics
1 answer:
Aloiza [94]3 years ago
3 0
The answer to this qution is 3 to the 1st power i think
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What are both of the zeros of x^2=10x-24
pantera1 [17]

Answer: 6,4

Step-by-step explanation: App called math-way it solves it however you would like and it’s free!

4 0
3 years ago
When 3 times a number is subtracted from 10, the result is the sum of the number and 22
Arada [10]

Answer:

x = -6

Step-by-step explanation:

Let the number be x

<u>Condition:</u>

=> 10-3x = x+22

<u><em>Let's Solve it:</em></u>

=> -3x-x = 22-10

=> -2x = 12

<em>Dividing both sides by -2</em>

=> x = -6

6 0
3 years ago
Read 2 more answers
. A box in a certain supply room contains four 40-W lightbulbs, five 60-W bulbs, and six 75-W bulbs. Suppose that three bulbs ar
yaroslaw [1]

Answer:

a) 59.34%

b) 44.82%

c) 26.37%

d) 4.19%

Step-by-step explanation:

(a)

There are in total <em>4+5+6 = 15 bulbs</em>. If we want to select 3 randomly there are  K ways of doing this, where K is the<em> combination of 15 elements taken 3 at a time </em>

K=\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455

As there are 9 non 75-W bulbs, by the fundamental rule of counting, there are 6*5*9 = 270 ways of selecting 3 bulbs with exactly two 75-W bulbs.

So, the probability of selecting exactly 2 bulbs of 75 W is

\frac{270}{455}=0.5934=59.34\%

(b)

The probability of selecting three 40-W bulbs is

\frac{4*3*2}{455}=0.0527=5.27\%

The probability of selecting three 60-W bulbs is

\frac{5*4*3}{455}=0.1318=13.18\%

The probability of selecting three 75-W bulbs is

\frac{6*5*4}{455}=0.2637=26.37\%

Since <em>the events are disjoint</em>, the probability of taking 3 bulbs of the same kind is the sum 0.0527+0.1318+0.2637 = 0.4482 = 44.82%

(c)

There are 6*5*4 ways of selecting one bulb of each type, so the probability of selecting 3 bulbs of each type is

\frac{6*5*4}{455}=0.2637=26.37\%

(d)

The probability that it is necessary to examine at least six bulbs until a 75-W bulb is found, <em>supposing there is no replacement</em>, is the same as the probability of taking 5 bulbs one after another without replacement and none of them is 75-W.

As there are 15 bulbs and 9 of them are not 75-W, the probability a non 75-W bulb is \frac{9}{15}=0.6

Since there are no replacement, the probability of taking a second non 75-W bulb is now \frac{8}{14}=0.5714

Following this procedure 5 times, we find the probabilities

\frac{9}{15},\frac{8}{14},\frac{7}{13},\frac{6}{12},\frac{5}{11}

which are

0.6, 0.5714, 0.5384, 0.5, 0.4545

As the events are independent, the probability of choosing 5 non 75-W bulbs is the product

0.6*0.5714*0.5384*0.5*0.4545 = 0.0419 = 4.19%

3 0
3 years ago
Solve x^2 x=0.factorise.
Semenov [28]
x^2\pm x=0\\\\x(x\pm1)=0\iff x=0\ or\ x\pm1=0\\\\\boxed{x=0\ or\ x=\mp1}\\\\if\ x^2+x=0\ then\ x=0\ or\ x=-1\\if\ x^2-x=0\ then\ x=0\ or\ x=1
4 0
3 years ago
What is the perimeter of the object (Hint: Not all numbers should be used to find your answer) (Provide number only in your answ
Sedaia [141]
Y 4 times 5 = square 5 divided by 6 = x times B so the anwser is sq 9
7 0
3 years ago
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