Answer:
Width of rectangle = 6 m
Length of rectangle = 11 m
Step-by-step explanation:
Let width of rectangle = w
Length of rectangle = 3w-7
Area of rectangle = 66 m²
We need to find length and width of rectangle
The formula used is: 
Putting values and finding w
Solve using quadratic formula: 
We have a=3, b=-7, c=-66
Putting values and finding w
We get values of w as w=6 and w=-3.6
As we know width cannot be negative, so considering w = 6
So, Width = 6
Length = 3w-7 = 3(6)-7 = 18-7 = 11
So, Width of rectangle = 6 m
Length of rectangle = 11 m
Answer:
(6, 5)
Step-by-step explanation:
Coordinates are written in the form (x, y), where x is the x-axis value that the point is in, in this case 6, and where y is the y-axis value, in this case 5.
Answer:
e^ (5 ln (x + 1)) = (x + 1)^5
Step-by-step explanation:
e5 In (x + 1) or did you mean e^ (5 ln (x + 1))
because then this would simplify a lot
e^ (5 ln (x + 1)) = e ^ (ln (x + 1)^5)
e^ (5 ln (x + 1)) = e ^ (ln (x + 1)^5) = (x + 1)^5
or did you mean (e^5) ( ln (x + 1)) = ln [(x+1)^(e^5)]
But I think you meant:
e^ (5 ln (x + 1)) = e ^ (ln (x + 1)^5) = (x + 1)^5
Answer:
74
Step-by-step explanation:
You just have to substitute r with 5.
Now, the equation looks like this:
Next, solve 
first according to PEMDAS
And equals 75
![\frac{\left[\begin{array}{ccc}1&5\\5\\\end{array}\right] }{75}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%265%5C%5C5%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%7D%7B75%7D)
Lastly, do 
which equals 74
![\frac{\left[\begin{array}{ccc}7&5\\-1\\\end{array}\right] }{74}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%265%5C%5C-1%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%7D%7B74%7D)
Therefore, 74 is your answer.
Answer:
Step-by-step explanation:
Yes
