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irga5000 [103]
4 years ago
13

2 – 1 + 5 x 4 x 11 Solve with PEMDAS

Mathematics
2 answers:
mash [69]4 years ago
8 0

Answer:

221

Step-by-step explanation:

2-1+5*4*11

2-1+20*11

2-1+220

1+220

221

tia_tia [17]4 years ago
4 0
The answer is 221. And it’s solved with PEMDAS
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Answer for this equation?
kicyunya [14]

Your answer is 13/45 or approximately 0.28!

6 0
3 years ago
I have attached 3 different problems, please could you help. Thank you
nydimaria [60]

Answer:

  1a) 210

  1b) 0.18

  2) 17.7 will fit (> 17)

  3) 515 cm^2

Step-by-step explanation:

1a) The sample of 25 is exactly 1/30 of the population of 750, so the number of orange cakes in the population will be 30 times the number in the sample.

The total number of orange cakes made on Monday is 30·7 = 210.

__

1b) The lowest number that will round to 5 is 4.5. The lowest probability that a cake is an orange cake is ...

  4.5/25 = 18/100 = 0.18

The lower bound on the probability that the cake is orange is 0.18.

____

2) The working shown is partly correct.

The possible error in the box dimension is 1/2 cm, so the box may be as short as 28 -1/2 cm = 27.5 cm.

The possible error in the disc case dimension is 1/2 mm = 0.05 cm, so the case may be as thick as 1.5 +.05 = 1.55 cm.

The minimum number discs that will fit in the case is (27.5 cm)/(1.55 cm) = 17.7. Thus, 17 cases will definitely fit in the box.

____

3) The shaded area will be the largest when the outside rectangle is the largest and the inside rectangle is the smallest. Errors in dimensions can be as much as 1/2 cm, so the Outside rectangle can be 42.5 cm by 21.5 cm. The inside rectangle can be as small as 27.5 cm by 14.5 cm.

Then the shaded area can be as large as ...

  (42.5)(21.5) -(27.5)(14.5) = 515 . . . . cm^2

3 0
4 years ago
Each triangle in the diagram is a reflection of another triangle across one of the given lines. How can you describe Triangle 2
Orlov [11]
Based on the given figure, triangle 2 is the reflection of triangle 3 across line l. Triangle 2 is also the reflection of triangle 1 across diagonal m.

Reflection is the transformation of a figure that shows the flip side of the figure. The reflection is congruent to the reflected image.

My answer is: <span>B. I and III only </span>



5 0
4 years ago
The radius of a circle is 10 cm. What is the approximate area of the circle? What is the exact area of the circle? Show your wor
faltersainse [42]

First let's review the area formula for a circle.

Area=πr^2

Now that we know the radius, r is 10. The area is

10*10*π=100π

I will approximate π to 3.14 although you could do it more precise or less precise. The final answer will be 100*3.14=314 squared centimeter.

Any question you have about this just ask in the comment of this answer :)

5 0
3 years ago
Someone, please help! I really don't understand congruent triangles
WARRIOR [948]

Answer:

  D.  (CPCTC)

Step-by-step explanation:

Your proof that the triangles are congruent is complete at the 4th step. In Step 5, you are asked to draw a conclusion about corresponding angles in those congruent triangles.

__

<h3>what is congruence?</h3>

Two geometric objects are congruent if they are identical in size and shape by any measure. If they are not labeled, you cannot tell them apart. Every measure of one is identical to the corresponding measure of the other. The location and orientation of congruent figures does not affect their congruence. You can move them, rotate them, flip them over, and they remain congruent.

This property, "corresponding parts of congruent triangles are congruent," is abbreviated "CPCTC." Once you have demonstrated objects are congruent, you can use this fact to relate measures of the objects that may not have been part of the demonstration.

<h3>proving congruence</h3>

<u>general</u>

We generally work with plane geometric figures that are polygons or have well-defined curved edges. Polygon figures are comprised of straight sides of fixed length. At each vertex, where sides meet, an angle is formed. Corresponding sides form corresponding angles.

The sides are generally named by the vertices at either end. The angles may be named by the vertex where it is located, or by the names of the sides that make it up.

In triangle ABC, for example, the vertices have labels A, B, and C. The sides are AB, AC, and BC. And the angles are A, B, and C, or BAC, ABC, ACB. (The vertex of the angle is the middle letter.)

To prove polygons are congruent, you must show corresponding angles are congruent, and corresponding sides are congruent. Generally, the number of sides will put constraints on the size of the angles. (A 6-sided polygon will have 6 angles that total 720°, for example.)

<u>triangles</u>

When the polygon is a triangle, the constraints on side lengths and angles generally mean there are shortcuts to proving congruence. The postulates that tell you what these are have been given mnemonic abbreviations. When we say, "angle" or "side" in this context, we are referring to congruent corresponding angles in the two triangles, or congruent corresponding sides.

  • AAS -- two consecutive angles and a side adjacent to one of them will prove congruence
  • ASA -- two angles and the side between them will prove congruence
  • SAS -- two sides and the angle between them will prove congruence
  • SSS -- three sides will prove congruence

These can also be applied to right triangles, where one angle is known to be 90°. In addition, there is a theorem that only applies to right triangles:

  • HL -- the hypotenuse and one leg will prove congruence. (Note that the hypotenuse is opposite the known 90° angle, so this is effectively an SSA congruence statement, only applicable to right triangles.)

<u>your proof</u>

The triangles in your figure have a side marked with a single hash mark. This means those corresponding sides in the two triangles are congruent to each other.

There is an angle marked with two (2) arcs in each triangle. This marking means those corresponding angles are congruent. Likewise for the angles marked with three (3) arcs. You will notice the 3-arc angle, 2-arc angle, and 1-hash mark side are in the same order in the two triangles. This means the AAS congruence postulate applies, as is claimed on line 4 of your proof.

<h3>using congruence</h3>

As you have seen, we only need to show <em>some</em> parts of a triangle are congruent in order to show <em>all</em> parts of the triangle are congruent. When we make a claim about corresponding parts that weren't an explicit part of the proof, we are essentially relying on the definition of congruent polygons. For triangles, that definition is summarized by the abbreviation CPCTC.

Line 5 of your 2-column proof is making a claim about corresponding angles of the triangle. That claim is supported by CPCTC.

_____

<em>Additional comment</em>

Choices A and C refer to congruence postulates, as discussed above. Those have no relation to the claim regarding angles ACB and XZY.

The "corresponding angles theorem" tells you corresponding angles are congruent where a transversal crosses parallel lines. It has no relation to the angles in this problem.

5 0
2 years ago
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