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3 years ago

Do anybody know this answer because I need help

Mathematics

1 answer:

Papessa [141]3 years ago

8 0

Answer:

x=-7

Step-by-step explanation:

divide 12 on both sides and that equals -7

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Margo borrows $1000, agreeing to pay it back with 5% annual interest after 15 months. How much interest will she pay?

GuDViN [60]

The answer is $50. Hope this helps!

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4 years ago

PLEASE HELP!!!!! Geometry

devlian [24]

Answer:

P = 49°

R = 131°

Q = 114°

S = 66°

Step-by-step explanation:

in a quadrilateral inscribed in a circle, the opposite angles are always supplementary, meaning they add up to 150

we are given opposite angles P and R (S is not given so we can't use Q and S)

P+R = 180

5y+14 + 15y + 26 = 180

20y + 40 = 180

20y = 140

y = 7

so...

P = 5(7) + 14 = 35 + 14 = 49

R = 180-49 (since opposite angles in inscribed quadrilaterals are supplementary) = 131

Q = (7)^2 + 65 = 49 + 65 = 114

S = 180-114 = 66

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3 years ago

A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the

Vedmedyk [2.9K]

(a) Using Newton's Law of Cooling, $\dfrac{dT}{dt} = k(T - T_s)$ , we have $\dfrac{dT}{dt} = k(T - 75)$ where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get $\dfrac{dT}{T - 75} = k dt$ . Integrate both sides to get $\ln|T - 75| = kt + C$ .

Since $T(0) = 185$ , we solve for C:
$|185 - 75| = k(0) + C\ \Rightarrow\ C = \ln 110$
So we get $\ln|T - 75| = kt + \ln 110$ . Use T(30) = 150 to solve for k:
$\ln| 150 - 75 | = 30k + \ln 110\ \Rightarrow\ \ln 75 - \ln 110= 30k \Rightarrow \\ k= \frac{1}{30}\ln (75/110) = \frac{1}{30}\ln(15/22)$

So

$\ln|T - 75| = kt + \ln 110 \Rightarrow |T - 75| = e^{kt + \ln110} \Rightarrow \\ \\
|T - 75| = 110e^{kt} \Rightarrow T - 75 = \pm110e^{(1/30)\ln(15/22)t} \Rightarrow \\
T = 75 \pm110e^{(1/30)\ln(15/22)t}$

But choose Positive because T > 75. Temp of turkey can't go under.

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} \\
T(45) = 75 + 110e^{(1/30)\ln(15/22)(45)} = 136.929 \approx 137{}^{\circ}F$

(b)

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} = 75 + 110(15/22)^{t/30} \\
100 = 75 + 110(15/22)^{t/30} \\
25 = 110(15/22)^{t/30} 
\frac{25}{110} = (15/22)^{t/30} \\
\ln(25/110) / ln(15/22) = t/30 \\
t = 30\ln(25/110) / ln(15/22) \approx 116\ \mathrm{min}$

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3 years ago

Ms. Higgins would like for her homework assignments to have three addition problems for every five subtraction problems. If she

NikAS [45]

Answer: 65

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solve for x

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3 years ago

The z-statistic for a sample of delmar's practice times is 1.41. how should this statistic be interpreted in terms of the hypoth

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Answer: c) There is not enough evidence to reject H0

Step-by-step explanation:

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3 years ago

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