Answer: All of these.
Explanation: Lets take a two-dimensional array alphabet[4][4]
Lets say this array contains the following elements: Example 1
a b c d
l i o n
f e l l
s t e m
These are the strings with same length. So this 2D array can contain strings of same length.
Now lets take another 2D array Example 2
a b c
h i n t
s o
e g g
2D array can have all these above mentioned elements. So it can contain strings of different lengths.
Now consider the Example 2. Some places for the elements are left. This isn't an issue for 2D array. So it can contain uninitialized elements too.
So the answer is All of above.
Answer:
hi your question lacks the necessary matrices attached to the answer is the complete question
1024 bytes
Explanation:
A) The minimum size of the cache to take advantage of blocked execution
The minimum size of the cache is approximately 1 kilo bytes
There are 128 elements( 64 * 2 ) in the preceding simple implementation and this because there are two matrices and every matrix contains 64 elements .
note: 8 bytes is been occupied by every element therefore the minimum size of the cache to take advantage of blocked execution
= number of elements * number of bytes
= 128 * 8 = 1024 bytes ≈ 1 kilobytes
Cmd.exe
------------------------------------------
REM PROGRAM TO DISPLAY AVERAGE OF TWO NUMBERS
CLS
INPUT “ENTER FIRST NUMBER”; A
INPUT “ENTER SECOND NUMBER”; B
INPUT “ENTER THIRD NUMBER”; C
AV = (A + B + C) / 3
PRINT “AVERAGE OF THREE NUMBERS”; AV
END
hope this helpz
