For the preceding simple implementation, this execution order would be nonideal for the input matrix; however, applying a loop i
nterchange optimization would create a nonideal order for the output matrix. Because loop interchange is not sufficient to improve its performance, it must be blocked instead. (a) What should be the minimum size of the cache to take advantage of blocked execution
hi your question lacks the necessary matrices attached to the answer is the complete question
1024 bytes
Explanation:
A) The minimum size of the cache to take advantage of blocked execution
The minimum size of the cache is approximately 1 kilo bytes
There are 128 elements( 64 * 2 ) in the preceding simple implementation and this because there are two matrices and every matrix contains 64 elements .
note: 8 bytes is been occupied by every element therefore the minimum size of the cache to take advantage of blocked execution
D (you may be unable to link to the site). The site cannot handle the large load of requests and are queued therefore, the response will be slowed down immensely. <span> </span>
The characteristic that is violated is Availability.
Explanation:
The network is passing data at mostly, it means performance is good. Junior network engineer is doing his job well then there is minimum chance of network failure or lack of manageability.
The scalability; range of computing capabilties can be managed by the engineer.
However, sometimes the core router might get crashed due to unavailability of the network that is not under the control of the engineer.
When the user has understood they're required to install the linux distribution to set up a specific program works better on such a RISC architecture. SPARC must therefore find the device from which it would work that following distribution for the Linux. It is a RISC and ISA that was previously designed through both Fujitsu and Sun.
