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Masja [62]
3 years ago
11

Describe the locus in space. points 4 mm from AB

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
7 0

<u>Answer with explanation:</u>

If we consider a flat, two dimensional graph, then the locus of all points that are  at a distance of 4mm from the line AB comprises of two lines, one on each of the sides.

While if we consider a 3 dimensional space, the locus of all  points that are at a distance of 4mm from the line AB will be a cylinder with a radius of 8mm.

ikadub [295]3 years ago
4 0

Answer:

Step-by-step explanation:

It would be a shape with 2 lines either side and parallel to AB with perpendicular distances of 4 mm from AB, and lengths equal to AB; and it will have 2 semi-circles of radius 4 mm attached to the ends of the parallel lines.

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kobusy [5.1K]

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The point-slope formula of a line:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

Substitute:

m=\dfrac{4-8}{-1-(-4)}=\dfrac{-4}{3}=-\dfrac{4}{3}\\\\y-8=-\dfrac{4}{3}(x-(-4))\\\\y-8=-\dfrac{4}{3}x-\dfrac{16}{3}\ \ \ \ |+8\\\\y=-\dfrac{4}{3}x-\dfrac{16}{3}+\dfrac{24}{3}\\\\y=-\dfrac{4}{3}x+\dfrac{8}{3}\ \ \ |\cdot3\\\\3y=-4x+8\ \ \ |+4x\\\\4x+3y=8

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3 years ago
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Fynjy0 [20]

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8 0
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Sindrei [870]

Given:

The expanded form of (x+s)(x-t) is x^2+Kx-40.

Where, s, t, K are positive integers.

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On comping both sides, we get

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Since s>t, therefore the possible values for (s,t) are (8,5), (10,4), (20,2) and (40,1).

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K=20-2=18          

K=40-1=39          

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Answer:

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