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Tatiana [17]
3 years ago
10

The following is a model showing the solution to an equation. x - 34 = 13 x - 34 + 34 = 13 + 34 x = 47 What property of equality

was used to solve the equation? a. subtraction b. addition c. multiplication d. division
Mathematics
1 answer:
yanalaym [24]3 years ago
8 0

Answer:

B.) Addition*Additive property of equality

Step-by-step explanation:

You add 34 to both sides of the equation to find what x was equal to

Hope I helped

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kaheart [24]
2x-3y=6
-3y=2x+6
y=-2/3x-2
So, the slope is -2/3
y=-2/3x+b
-3=-2/3(9)+b
-3=-6+b
-3/(-6)=b
1/2=b
So, the equation is y=-2/3x+1/2
5 0
4 years ago
Write fractions I order from least to greatest.
alekssr [168]
2/5 is equal to 0.4
1/3 is equal to 0.33
5/6 is equal to 0.83
4/8 is equal to 0.5
5/12 is equal to 0.42
1/6 is equal to 0.17
7/100 is equal to 0.07
9/10 is equal to 0.9
4/5 is equal to 0.8

so from least to greatest: 7/100, 1/6, 1/3, 2/5, 5/12, 4/8, 4/5, 5/6, 9/10
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3 0
3 years ago
Use sum identities to derive one double angle identity for cosine
tester [92]

Answer:

  • cos(2Ф) = cos²(Ф) -sin²(Ф)
  • cos(2Ф) = 1 -2sin²(Ф)
  • cos(2Ф) = 2cos²(Ф) -1

Step-by-step explanation:

The angle sum formula for cosine is ...

  cos(α+β) = cos(α)cos(β) -sin(α)sin(β)

When we have α = β = Ф, this becomes ...

  cos(Ф+Ф) = cos(Ф)cos(Ф) -sin(Ф)sin(Ф)

  cos(2Ф) = cos²(Ф) -sin²(Ф)

The "Pythagorean identity" can be used to write this in terms of sine or cosine.

  cos(2Ф) = (1 -sin²(Ф)) -sin²(Ф)

  cos(2Ф) = 1 -2sin²(Ф)

or

  cos(2Ф) = cos²(Ф) -(1 -cos²(Ф))

  cos(2Ф) = 2cos²(Ф) -1

3 0
3 years ago
Determine the mode for the following set of tests score 63,70,75,80,85,85.85,92,92,95,99
Mariulka [41]

The mode is 85, because it is the most occurring in the data set.

hope that helps :)

6 0
3 years ago
Read 2 more answers
Enter the ZEROS of the function below. Select 2 answers:
nexus9112 [7]
F(x) = x² - 13x + 30

f(x) = x² - 3x - 10x + 30 = 0

f(x) = x(x - 3) -10(x - 3) = 0

f(x) = (x-3)(x-10) = 0

f(x) = 3 OR 10

In short, Your Answer would be Option B & D

Hope this helps!
5 0
3 years ago
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