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Andreyy89
3 years ago
7

Julio, Kira, and Ida each want to buy art supplies. Julio wants to spend between $6 and $7. Kira wants to spend between $4 and $

6. Ida wants to spend between $8 and $9. Drag items to the box under each person's name to show what they could have bought. Julio, Kira, and Ida each want to buy art supplies. Julio wants to spend between $6 and $7. Kira wants to spend between $4 and $6. Ida wants to spend between $8 and $9. Drag items to the box under each person's name to show what they could have bought.

Mathematics
1 answer:
Lorico [155]3 years ago
4 0

Answer: image below is the answer

Step-by-step explanation:

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RATING BRAINLIEST Which of the following demonstrates the Distributive Property?
ra1l [238]

Answer:

D: 4(2a+3)=8a+3

Step-by-step explanation:

4x2a = 8a and 4x3 = 12

4 0
2 years ago
Read 2 more answers
Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 9t + 9 cot(t/2), [π/4, 7π/4]
agasfer [191]

Answer:

the absolute maximum value is 89.96 and

the absolute minimum value is 23.173

Step-by-step explanation:

Here we have cotangent given by the following relation;

cot \theta =\frac{1 }{tan \theta} so that the expression becomes

f(t) = 9t +9/tan(t/2)

Therefore, to look for the point of local extremum, we differentiate, the expression as follows;

f'(t) = \frac{\mathrm{d} \left (9t +9/tan(t/2)  \right )}{\mathrm{d} t} = \frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2}

Equating to 0 and solving gives

\frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2} = 0

t=\frac{4\pi n_1 +\pi }{2} ; t = \frac{4\pi n_2 -\pi }{2}

Where n_i is an integer hence when n₁ = 0 and n₂ = 1 we have t = π/4 and t = 3π/2 respectively

Or we have by chain rule

f'(t) = 9 -(9/2)csc²(t/2)

Equating to zero gives

9 -(9/2)csc²(t/2) = 0

csc²(t/2)  = 2

csc(t/2) = ±√2

The solutions are, in quadrant 1, t/2 = π/4 such that t = π/2 or

in quadrant 2 we have t/2 = π - π/4 so that t = 3π/2

We then evaluate between the given closed interval to find the absolute maximum and absolute minimum as follows;

f(x) for x = π/4, π/2, 3π/2, 7π/2

f(π/4) = 9·π/4 +9/tan(π/8) = 28.7965

f(π/2) = 9·π/2 +9/tan(π/4) = 23.137

f(3π/2) = 9·3π/2 +9/tan(3·π/4) = 33.412

f(7π/2) = 9·7π/2 +9/tan(7π/4) = 89.96

Therefore the absolute maximum value = 89.96 and

the absolute minimum value = 23.173.

7 0
3 years ago
Here is another Guy's... This one is hard..12 Points? First one to answer with a great explanation gets brainlest (:!
schepotkina [342]

Answer:

25/16

Step-by-step explanation:

(4/5)^−2

=

(4/5)^−2

=

(5/4)^2

=

(5/4)*(5/4)


=


5*5/4*4


=


5^2/4^2

=


25/16


(Decimal: 1.5625)

7 0
3 years ago
If g(x)= x^2-2x-6 and h(x)= 2x^2-5x+2 find (h-g) (-2)
Natalka [10]

Answer:

<h2>(h - g)( - 2) = 18</h2>

Step-by-step explanation:

g(x) = x² - 2x - 6

h(x) = 2x² - 5x + 2

To find (h-g) (-2) we must first find h - g(x)

To find h - g(x) subtract g(x) from h(x)

We have

<h3>(h - g)(x) =  {2x}^{2}  - 5x + 2 - ( {x}^{2}  - 2x - 6)  \\  =  {2x}^{2}  - 5x + 2 -  {x}^{2}  + 2x + 6 \\  =  {2x}^{2}  -  {x}^{2}  - 5x + 2x + 2 + 6</h3><h3>(h - g)(x) =  {x}^{2}  - 3x + 8</h3>

To find (h-g) (-2) substitute the value of x that's - 2 into (h - g)(x) that's replace every x in (h - g)(x) by - 2

That's

<h3>(h - g)( - 2) =  ({ - 2})^{2}  - 3( - 2) + 8 \\  = 4 + 6 + 8 \\  = 10 + 8</h3>

We have the final answer as

<h3>(h - g)( - 2) = 18</h3>

Hope this helps you

7 0
3 years ago
Sugar was traditionally produced and sold as sugarloaves, which are cones of sugar wrapped in paper. Find the total surface area
Zolol [24]

Answer:

A = 326,73 cm²

Step-by-step explanation:

The area of a circular cone is area of the base (A₁ ) plus area lateral ( area of a circular sector of radius the slant height )

Then we proceed to calculate the area of the base A₁

diameter of circular base is 8 cm then the radius is 4 cm and the area is:

A₁ = π*r²  =  3,14* (4)²

A₁ = 3,1416*16   =  50,2656 cm²

Now Lateral area of the cone (A₂) is equal to the area of a circular sector with radius the slant height. We will calculate it, taken into account that this circular sector is part of a circle of radius the slant height.

Between the area of circular sector with radius the slant height and the area of the circle with the same radius there is a linear relation. That is we can calculate area of a circular sector by rule of three as follows:

The length of the circular sector is the length of the circle of the base of the cone, that is:

L = 2*π*(4)

L = 2*3,1416*4

L = 25,1328 cm

Then we have a circular sector of length 25,1328 cm

The area of the circle of radius 22 cm is:

A(c)  = π*(22)²     ⇒   A(c)  = 1520,5344 cm²

And the length of this circle is:

L(c)  =  2*π*(22)     ⇒   138,2304 cm

Then we apply a rule of three

For a length of      138,2304 cm  ⇒⇒⇒  (area)  1520,5344 cm²

Then for a length of  25,1328 cm   ⇒⇒⇒(area)   A₂ (??)

Therefore:

A₂ =  (25,1328)*1520,5344)/ 138,2304

A₂ = 276,4608 cm²

Then total area of the cone is:

A = A₁  +  A₂

A =  50,2656  +276,4608

A  = 326,7264 cm²

Round answer  A = 326,73 cm²

8 0
3 years ago
Read 2 more answers
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