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3 years ago

When evaluating (6x+9)^2 - 5 for x = 1, the given value of 1 is substituted for what part of the expression?

Mathematics

2 answers:

Veronika [31]3 years ago

7 0

The answer is C, I took the test.

Naya [18.7K]3 years ago

5 0

The correct answer would be C. The variable

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What is the primary difference between exponential and linear functions?

Yanka [14]

Answer:

Step-by-step explanation:

We know that the growth of a linear function will always be constant. So, that eliminates B and C.

A quadratic function can be a function such as $x^2$ , or $5x^2+7x$ , etc.

An exponential function wouldn't be $x^2$ , it would be $2^x$ ! Or $3^x$ , or $(1.738283)^x$ , etc. Therefore, D is eliminated.

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2 years ago

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3 years ago

Read 2 more answers

A function is given: f (x) = 2x + 3 What is the value of f(-2)?

Nadusha1986 [10]

Answer:

f(-2) = -1

Step-by-step explanation:

-2 is x, so replace x as -2 into the equation

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f (-2) = -4 + 3

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5 0

3 years ago

What are the missing angles? What is the relationship between the measures of supplementary angles?

goldenfox [79]

Answer:

6=100°

8=80°

7=100°

9=80°

Step-by-step explanation:

If 6 is 100°

in a straight line theres 180 degrees

180-100=80°

8 is 80°

opposite 6 to 7 there are parallel corresponding angles meaning the angle opposite it will be the same. 8 with 9.

same with

5 0

3 years ago

How do you simplify this? x²y+xy² / y²+2/5 × xy

polet [3.4K]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

How do you simplify this?
x²y+xy² / y²+2/5 × xy

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

$\sf\frac{ { x }^{ 2 } y+x { y }^{ 2 } }{ { y }^{ 2 } + \frac{ 2 }{ 5 } \times xy } \\$

Factor the expressions that are not already factored.

_____

How to factorise :-

NUMERATOR $\downarrow$

$\sf \: x ^ { 2 } y + x y ^ { 2 }$

Factor out xy.

$\sf \: xy\left(x+y\right)$

DENOMINATOR $\downarrow$

$\sf{ y }^{ 2 } + \frac{ 2 }{ 5 } \times xy \\$

Factor out 1/5.

$\sf \: {\frac{1}{5}y\left(2x+5y\right)} \\$

_____

Continuing...

$\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)} \\$

Cancel out y in both the numerator and denominator.

$\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)} \\$

Expand the expression.

$\sf\frac{x^{2}+xy}{\frac{2}{5}x+y} \\$

This can further simplified to as $\downarrow$

$= \boxed{\boxed{\bf\frac{5x\left(x +y\right)}{2x+5y}}}$

3 0

3 years ago