If <em>a</em> is fixed and <em>b</em>,<em>c</em> are unknowns then the equation <em>b</em>+<em>c</em>=10-<em>a</em> has 11-<em>a</em> solutions. They are pairs (b,c): (0,10-a), (1,9-a), (2,8-a), ... (10-a,0). As <em>a</em> runs from 0 to 10 we have total number of solutions (11-0)+(11-1)+...(11-1)=11+10+...+1=(1+11)*11/2=66.
It would be 5*5*5 which is 125 :D
Answer:
A3
B1
C2
Step-by-step explanation:
Answer: Choice D, -5x^3 + 8
A binomial consists of two terms being added or subtracted. The two terms are -5x^3 and 8. The term -5x^3 has a leading coefficient -5 and exponent 3. The largest exponent determines the degree of the polynomial. The 8 is constant as there are no variables attached or multiplying with it.
