Answer:
it will take 3 hours long
Her final score should be 21. You can add both 3 1/2 and 3 1/2 which will give you 7. Then substract it from 28.
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
Y² + 8y - 33 :
Break the expression into groups for formula ax²+ bx+c :
= (y²- 3y) + (11y - 33 )
Factor y from y² - 3y => y (y - 3)
Factor out 11 from 11 y - 33 => 11 (y - 3)
= y ( y- 3 ) + 11 ( y - 3 )
Factor out common term (y - 3 ) :
= ( y - 3 ) ( y + 11 )
hope this helps!
Answer:
636.17251
Step-by-step explanation:
V = πr^2h = π·4.5^2·10 ≈ 636.17251
