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3 years ago

13

Please help!!! How do you count (-3y^2+5y) (4y+7)??

1 answer:

levacccp [35]3 years ago

6 0

You must distribute each value like this:

$(-3y^2+5y) (4y+7)\\ \\ (-12y^3-21y^2+20y^2+35y)\\ \\ (-12y^3-y^2+35y)$

Hope that helps!

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