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sdas [7]
3 years ago
13

Please help!!! How do you count (-3y^2+5y) (4y+7)??

Mathematics
1 answer:
levacccp [35]3 years ago
6 0

You must distribute each value like this:

(-3y^2+5y) (4y+7)\\ \\ (-12y^3-21y^2+20y^2+35y)\\ \\ (-12y^3-y^2+35y)

Hope that helps!

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A. 1/16=x/56.............
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From the side of a hill wai-kin looks up at the top of a nearby vertical cliff at an angle of elevation of 36 degrees and looks
oksano4ka [1.4K]

Answer:

881.5 meters.

Step-by-step explanation:

The horizontal plane at the level of wai-kin's eyes divide the height of the cliff into two parts. Let the upper part be represented by x and the lower part be represented by y.

The height of the cliff = x + y

Applying the appropriate trigonometry functions.

To determine the value of x;

Tan θ = \frac{opposite}{adjacent}

Tan 36^{o} = \frac{x}{490}

⇒ x = 490 x Tan 36^{o}

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To determine the value of y;

Tan θ = \frac{opposite}{adjacent}

Tan 47^{o} = \frac{y}{490}

⇒ y = 490 x Tan 47^{o}

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      = 525.476

y = 525.5 meters

Therefore,

The height of the cliff = x + y

                                   = 355.985 + 525.476

                                   = 881.461

The height of the cliff is 881.5 meters.

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

X^2+5x-50

Step-by-step explanation:

X^2-5x+10x-50

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Read 2 more answers
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