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andrey2020 [161]
2 years ago
10

Josey got an answer of 167 remainder 4 for 505 divided 3. Explain and correct josey's error

Mathematics
1 answer:
liubo4ka [24]2 years ago
6 0

Answer:

505 / 3 = 168.3...

Step-by-step explanation:

Everything was right until the 7

3 goes into 25 8 times because 3 x 8 = 24

there should only be a remainder of 1 which translates into .3 (repeating)

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Hikers spent the following amounts of time (in minutes) to complete a nature hike:48, 46, 52, 57, 58, 52, 61, 56.
Solnce55 [7]
For A for the mean just add them all up which would be which is 430 and divide by the number of numbers there is so 430 divided by 8 = 53.75 and the median order them from least to greatest and find the one in the middle which is 52 and 56 when there's two just add them and then divide it by 2 which is 54

Hope this helped :)
8 0
3 years ago
Read 2 more answers
Simplify the expression where possible.<br><br> (-5 x 2 ) 3 help please!
MAXImum [283]
The answer to (-5 × 2) 3 = -30.
8 0
2 years ago
One of ten different prizes was randomly put into each box of a cereal. If a family decided to buy this cereal until it obtained
Reptile [31]

Answer:

29.29

Step-by-step explanation:

The first trial among a distribution of independent trials with a constant success probability follows a geometric probability.

The expected value of a negative binomial is the reciprocal of its success probability <em>p.</em>

<em>E(X)=</em>1/<em>p</em>

At the first draw, we only selected one of the 10 prizes and so 1 draw gives a success

<em>E(X)=</em>1/<em>p</em>

<em>E(X1)</em>=1

After the first prize is drawn, we are interested in the first time (success), that we draw another prize that is different (<em>p</em>=9/10)

E(X2)=1/9÷10

E(X2)= 10/9

After the first prizes have being drawn, we now interested in the first time success that we draw a different prize from the first 2

E(X3)=1/8÷10

E(X3)=10/8

E(X3)=5/4

After the first three prizes have been drawn, we are now interested in the success of a first time draw for the 4th different prize

E(X4)=1/7÷10

E(X4)=10/7

Fifth different prize

E(X5)=1/6÷10

E(X5)=10/6

E(X5)=5/3

Sixth different prize

E(X6)=1/5÷10

E(X6)=10/5

E(X6)=2

Seventh different prize

E(X7)=1/4÷10

E(X7)=10/4

E(X7)=5/2

Eighth different prize

E(X8)=1/3÷10

E(X8)=10/3

Ninth different prize

E(X9)=1/2÷10

E(X9)=10/2

E(X9)=5

After the 9 different prizes have been drawn, we are interested in the first time we will draw the tenth different prize

E(X10)=1/1÷10

E(X10)=10

Add up all corresponding values;

<em>E(X)=</em>E(X1)+E(X2)+E(X3)+E(X4)+E(X5)+E(X6)+E(X7)+E(X8)+E(X9)+E(X10)

<em>E(X)=</em>1+10/9+5/4+10/7+5/3+2+5/2+10/3+5+10

<em>E(X)</em>= 29.29

Note: Those values in <em>E(X), </em>should be written the way it will in standard algebra ie they should be small.

4 0
3 years ago
A hockey team wants to sell $500 worth of tickets. If each ticket costs $10, how many tickets
Tanzania [10]
Given ,

Hockey team wants to sell 500$ worth of tickets

Cost of each ticket = $10

To meet its goal ,
Number of tickets to be sold = total cost/cost of one ticket

=> Number of tickets to be sold = 500/10 = 50 tickets .
5 0
1 year ago
Read 2 more answers
ASAP! BRAINLIEST!
nasty-shy [4]

Answer:

The average rate of change from 3 to 6 storms = 0.04

Step-by-step explanation:

Let number of Storms = N

And Predicted Gas Price = P

it is required to find the average rate of change from 3 to 6 storms.

At N = 3 ⇒ P = $2.44

At N = 6 ⇒ P = $2.56

So, the average rate of change = \frac{2.56-2.44}{6-3}=\frac{0.12}{3}=0.04

5 0
2 years ago
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