Answer:
Step-by-step explanation:
I'm going to start with problem 3. You need to become familar with the kind of tricks teachers play on you.
Problem 3 depends on getting RS = RW.
RT = RT Reflexive property
<STR = <WTR A straight line having 1 rt angle actually has 2
ST = TU They are marked as equal
Triangle STR=Triangle WTR SAS
RS = RW Corresponding parts of = triangles are =
8x = 6x + 5 Subtract 6x from both sides
8x -6x = 6x - 6x + 5 Combine
2x = 5 Divide by 2
2x/2 = 5/2
x = 2.5
RU = 6*2.5 + 5
RU = 15 + 5
RU = 20
Now we can play with Question 4.
This question depends on the method used in three, although not entirely.
What you need to know is that W is on RT when you take a ruler and make RT longer. You can put W anywhere as long as it is on RT when it is made longer.
Directions
Make RT longer. Draw down and to your right.
Put a point anywhere on the length starting at T. Label this new point as W. There's your W. It goes anywhere on the part of RT made longer.
Draw UW.
Label UW as 8
Now draw another line from S to W. Guess what? By the methods used in question 3, it's also 8. So SW = 8
TW = TW Reflexive
<UTW = STW Same reason as in 3. UtW is a right angle
UT = ST Given (the marking tells you so.
ΔUTW = ΔSTW SAS
UW = SW Corresponding parts of = triangles are =
SW = 8
