U= 9 divide by 6
U=9/6
=3/2
The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
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Answer:- D shows the triangle pairs which can be mapped to each other using a single translation.
Explanation:-
Translation is a rigid transformation which creates a congruent image as that of the original figure such that the distance between the each point of the original figure and the image is fixed and same.
The translation mapping is given by (x,y)→(x+h,y+k) ,where h is the distance of the x coordinate of the each point of the original figure to the image and k is the distance of the y coordinate of the each point of the original figure to the image.
In figure D we can see that the distance between each point of ΔCED is equal to the distance between each point of ΔMPN. Thus it shows the triangle pairs which can be mapped to each other using a single translation.
Answer:
1/216
Step-by-step explanation:
Answer:
true ...
believe it or not there is an exponential sequence that can make that
result
f(x) = 
<u>x /// 2(x+2) -1</u>
-1 /// 1
0 /// 3
1 /// 5
2 /// 7

Step-by-step explanation: