Answer:
Step-by-step explanation:
In a coin toss the probability of tossing a head is 0.5 (50% head/50% tails)
If n is the number of rounds and 2n the number of coins tossed (one for each player), the probability of having m heads tossed is:
R is the number of cases (combination of coins tossed) that gives a m number of heads. Each case has a probability of 
so:
<u>For example, to toss 4 heads in 5 rounds: </u>
<span>(4^4)^2
= 4^(4*2)
=4^8
answer
4^8</span>
U need to simplify 5×5 to 25,move the negative to the left, then simplify the brackets
Given that PQ and RS are drawn with KL as tranversal intersecting PQ at M and RS at point N. Angle QMN is congruent to angle LNS because they are alternate to each other. The theorem that Kari can use to show that the meansure of QML is supplementary to the measure of angle SNK is Alternate Exterior Angles Theorem.
This is because angle KNR is equal to QML by alternate exterior angles theorem so is angle MLP and SNK
Answer: (1,4)
Explanation: The domain looks at the x coordinates and (1,4) is the only x coordinate in the range given (due to the bracket)
