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goldfiish [28.3K]
4 years ago
7

Why doesnt the number of neutrons identify an element

Chemistry
1 answer:
Goryan [66]4 years ago
8 0

You look at the atomic mass.. The number of neutrons is different for different individual atoms of the same element, each atom is also known an isotope. Looking at a periodic table, the atomic mass listed is the average atomic mass for all isotopes of that element found in nature.

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Glucose is a product of photosynthesis. where do the carbon atoms in glucose come from?
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Carbon atoms in glucose come from carbon dioxide.
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7. I have 2.50 x 1023 atoms of titanium. How many moles of titanium dol<br> have?
algol13

Answer:

0.42mole

Explanation:

Given parameters:

Number of atoms of titanium  = 2.5 x 10²³atoms

Unknown:

Number of moles  = ?

Solution:

To solve this problem, we must understand that a mole of any substance contains the Avogadro's number of particles.

              6.02 x 10²³ atoms makes up 1 mole of an atom

              2.5 x 10²³ atoms will contain \frac{2.5 x 10^{23} }{6.02 x 10^{23} }   = 0.42mole

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3 years ago
Which soil sample is least permable?
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20. Explain, in terms of valence electrons, why the bonding in NaCl is ionic.
Ivahew [28]

Answer:

MgO, is similar to the bonding in barium chloride, BaCl2. The bonding in each compound involves a transfer of valence electrons from the metal to the nonmetal; both metals lose all of their valence electrons

Explanation:

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4 0
3 years ago
Suppose a 250 ml flask is filled with 1.3mol of O2 and 1.5 mol of NO. The following reaction becomes possible: The equilibrium c
bonufazy [111]

<u>Answer:</u> The equilibrium molarity of oxygen gas is 7.1 M

<u>Explanation:</u>

We are given:

Moles of oxygen gas = 1.3 mole

Moles of NO = 1.5 moles

Volume of the flask = 250 mL = 0.250 L   (Conversion factor:  1 L = 1000 mL)

To calculate the molarity, we use the equation:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume of solution (in L)}}

Molarity of oxygen gas = \frac{1.3}{0.25}=5.2M

Molarity of NO = \frac{1.5}{0.25}=6.0M

The chemical equation follows:

                              O_2+N_2\rightleftharpoons 2NO

Initial:                  5.2    -           6.0

At eqllm:          5.2+x     +x      6.0-2x

The expression of K_c for above equation follows:

K_c=\frac{[NO]}{[O_2][N_2]}

K_c=0.394   (Assuming)

Putting values in above equation, we get:

0.394=\frac{(6.0-2x)^2}{(5.2+x)\times x}\\\\-3.606x^2+26.0488x-36=0\\\\x=1.9,5.4

Neglecting the value of x = 5.4 because this cannot be greater than the initial value.

Concentration of oxygen gas at equilibrium = (5.2 + x) = 5.2 + 1.9 = 7.1 M

Hence, the equilibrium molarity of oxygen gas is 7.1 M

8 0
3 years ago
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