It depends if it is
1. 3x+(1/14)=(2x)/8 or
2. (3x+1)/14=(2x)/8
if it is 1
1.
3x+(1/14)=2x/8
simplify 2x/8
2x/8=x/4
3x+(1/14)=x/4
find least common multiple of 14 and 4
factors of 14=2 and 7
factors of 4 are 2 and 2 so LCM=2 times 2 times 7=28
multiply both sides by 28
84x+2=7x
subtract 7x from both sides
77x+2=0
subtract 2 from both sides
77x=-2
divide both sides by 77
x=-2/77
2.
(3x+1)/14=2x/8
simpify 2x/8
2x/8=x/4
(3x+1)/14=x/4
find least common multiple of 14 and 4
factors of 14=2 and 7
factors of 4 are 2 and 2 so LCM=2 times 2 times 7=28
multiply both sides by 28
(2)(3x+1)=7x
distribute
6x+2=7x
subtract 6x from both sides
2=x
Equation 1 would be: 3a+2C
Equation 2 would be: 5a+3C
It's $0.44 cents my good friend......
f(x) = 5x − 1 and g(x) = 2x^2 + 1
(f × g)(x) = (5x − 1)(2x^2 + 1)
(f × g)(x) = 10x^3 - 2x^2 + 5x - 1
Substitute x = - 3
(f × g)(-3) = 10(-3)^3 - 2(-3)^2 + 5(-3) - 1
(f × g)(-3) = 10(-27) - 2(9) -15 - 1
(f × g)(-3) =-270 - 18 - 16
(f × g)(-3) = -236
Answer
- 236
Answer: 5
Step-by-step explanation:
